2007-01-02 10:01:47 · 14 answers · asked by Anonymous in Cars & Transportation ➔ Rail
Hello =)
Relative to a stationary observer, who was not on the train, yes.
Relative to an observer who was on the train, no.
There is no "absolute objectivity" in physics anymore....despite what they continue to teach in highschool.
Namaste, and Happy New Year,
--Tom
2007-01-02 10:04:25 · answer #1 · answered by glassnegman 5 · 0⤊ 2⤋
Not if you are running in the opposite direction that the train was traveling.
Definately not if the train went through a low clearance tunnel.
and...
Not if you fell between the cars and got cut in half, which is most likely what would happen, so stay off the train.
2007-01-02 16:21:58 · answer #2 · answered by QueenA 3 · 0⤊ 0⤋
Yes, your speed over ground would be the combined speed (if running in the same direction of train travel). It would not be your speed in relation to the train, only over ground.
2007-01-02 10:06:21 · answer #3 · answered by qmstr725 3 · 1⤊ 0⤋
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2016-10-06 08:37:28 · answer #4 · answered by regula 4 · 0⤊ 0⤋
yes, if you're running the same direction. if you're running the other way, it's speed of train minus running speed.
2007-01-02 10:04:56 · answer #5 · answered by Dale B 3 · 0⤊ 0⤋
speed is distance against time velosity is the first differential of this and acceleration the second and each is an instantainious deviation from the former and brakeing is negative acceleration so it would be + or - acceleration from the trains velosity
2007-01-02 10:50:58 · answer #6 · answered by Mick W 7 · 0⤊ 0⤋
yes, if you were running towards the front of the train.
2007-01-02 10:04:40 · answer #7 · answered by bluecollaraddict 3 · 0⤊ 0⤋
Yes - easy example is walking while on a moving walkway, like at an airport.
2007-01-02 15:25:52 · answer #8 · answered by donatellos_green_turtle_ass 1 · 0⤊ 0⤋
Yes.
2007-01-02 16:34:58 · answer #9 · answered by luther 4 · 0⤊ 0⤋
That only happens in the movies....ever tried to run into a 40mph head wind?..
2007-01-02 10:47:16 · answer #10 · answered by Anonymous · 2⤊ 0⤋