what's the compound of A and B?

Question

CH3-CH(CH3)-CH2-CH2OH undergoes oxidation to produce A.Then,A reacts with CH3CH2OH to produce B..what's A and B?

Answer 1

I am assuming complete oxidation of
CH3-CH(CH3)-CH2-CH2OH which is 3-methylbutanol

we get CH3-CH(CH3)-CH2-COOH as compound A which is
3-methylbutanoic acid

A reacts with CH3CH2OH, ethanol to produce B

CH3-CH(CH3)-CH2-COOH + CH3CH2OH
-----> CH3-CH(CH3)-CH2-CO-O-CH2CH3 which is compound B
named as ethyl-3-methylbutanoate

Answer 2

Your starting product is 3-methylbutan-1-ol, which is a primary alcohol. You actually have 2 optional answers since primary alcohols can be oxidised to aldehydes or carboxylic acids, depending on whether you distil or reflux.

a) The most probably answer is that the alcohol is oxidised all the way to the carboxylic acid, 3-methylbutanoic acid, CH3-CH(CH3)-CH2-COOH . This then reacts with ethanol to produce the ester ethyl 3-methylbutanoate - CH3-CH(CH3)-CH2-COO-CH2-CH3 .

b) the second possible answer is that the alcohol is oxidised only to an aldehyde, which would be 3-methylbutanal, CH3-CH(CH3)-CH2-CHO . This reacts with ethanol to produce the hemi-acetal CH3-CH(CH3)-CH2-CH(OH)-OCH2CH3 . This reacts further with the alcohol, combined with elimination of water, to produce the acetal CH3-CH(CH3)-CH2-CH-(OCH2CH3)2 .

Given the complexity of the second reaction, I would think that the first option is your more probably answer.

Answer 3

C02-h20