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passing through (0,3) and parallel to y=4x-2
passing through (2,0)and perpendicular tp y=x/3-1

2006-12-30 20:07:51 · 3 answers · asked by avenger 2 in Science & Mathematics Mathematics

3 answers

uhh... that is.. easy..

parallel functions have equal slopes and perpendicular functions have negative reciprocal slopes

for the first, the slope is the same, use 4 as slope and build the function with the x and y provided

the second, the slope is -3 and use the x and y provided to make the function, use point slope or watever its called

y-y1=m(x-x1)

2006-12-30 20:15:25 · answer #1 · answered by myFEARisALIEN! 2 · 0 1

A linear equation is always of the form y = ax+b, where a is the slope. The equation of a line parallel to another line has the same slope (a) but different intercept (b). In your first question, you can see immediately what the slope of the new line has to be; use that slope for a in the general formula, then put in the x and y values of the point given to solve for the intercept.

The second is done the same way, except that the slope of the perpendicular line is minus the reciprocal of the first line. (a' = -1/a)

2006-12-31 04:16:48 · answer #2 · answered by gp4rts 7 · 0 1

how bout you ask your teacher as these are obviously homework questions. and i dont particularly want to help you.

2006-12-31 04:09:24 · answer #3 · answered by panicatthediscoobsessed 2 · 1 0

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