addition and subtraction help??? with variables?

Question

5/ab + 3/b=

1/r - 8/dr=

2/xy^2 + 8/x^2y=

x/6 - 1/3x=

5a/b^2 - 6a/b=

Answer 1

5/ab + 3/b=(5+3a)/ab

1/r - 8/dr=(d-8)/dr

2/xy^2 + 8/x^2y=2(x+4y)/x^2y^2

x/6 - 1/3x=(x^2-2)/6x

5a/b^2 - 6a/b=a(5-6b)/b^2

Answer 2

5/ab + 3/b
Multiply 3/b by a/a so the denominators are equal.
5/ab+3a/ab
=5+3a/ab

1/r-8/dr
Multiply 1/r by d/d
=d-8/dr

2/xy^2 + 8/x^2y
=2/xyy + 8/xxy
Multiply first term by x/x
Multiply second term by y/y
=2/xxyy + 8/xxyy
=2/((x^2)(y^2)) + 8/((x^2)(y^2))
=10/((x^2)(y^2))

x/6-1/3x
Multiply x/6 by 0.5x/0.5x
0.5x^2/3x-1/3x
=(0.5x^2-1)/3x

5a/b^2-6a/b
Multiply second term by b/b
=5a/b^2-6ab/b^2
=5a-6ab/b^2

Look, you need to put your parentheses, or else the results won't make sense. I'm trying my best to see what you're really trying to say.

Answer 3

5/ab + 3/b= multiply both terms by b so u have 5b/ab + 3b/b. cancel both the two b's because its the same as 2/2 so its 1
so you have final answers: 5/a + 3 or 5 + 3a

1/r - 8/dr= again multiply both terms by r and cancel it.
final answerss: 1 - 8/d or d - 8

2/xy^2 + 8/x^2y= multiply both terms by x^2y^2 so u have
1st term:
2x^2y^2/xy^2- cancel variables if necessary = 2x
2nd term:
8x^2y^2/x^2y - cancel again = 8y

then we will have 2x + 8y but they both have a GCF (greatest common factor) of 2 so divide both terms by 2 so we will have
final answer:(after factorization)
2(x+4y)

x/6 - 1/3x= we must first remove the x from 1/3x and it has a GCD(denominator) of 6 so multiply both of them by 6x. we will have(after cancelation): 6x^2/6= x^2
2nd term: 6x/3x= 2
so final anwer is
x^2 - 2 or
x(x-2) (after factorization)

5a/b^2 - 6a/b= GCD is b^2 so cancel again multiply both terms by b^2
we have(after cancelation)
1st term: 5a
2nd term: 6ab
now LCD is a so divide both of them by a u have:
final answer:
a(5 - 6b)

Answer 4

1. First: determine the Least Common Denominator > ab. Combine the terms but, repeat them once.

Second: multiply the missing terms to get the LCD by each fraction (top and bottom).

5/ab + a(3)/a(b)
5/ab + 3a/ab

Third: combine the numerators.

(5 + 3a)/ab

*I encourage you to try the rest. Providing every answer isn't going to help you complete these on your own :-)
2. follow the same steps from (1) > LCD = dr
3. follow the same steps from (1) > LCD = (x^2)(y^2)
4. follow the same steps from (1) > LCD = 3x(6) >18x
5. follow the same steps from (1) > LCD = b

Answer 5

5/ab + 3b = (5+3a)/ab
1/r- 8/dr= (d-8)/dr
2/xy^2 + 8/x^2y= (2x^y + 8y^2)/ x^2y*y^2
x/6-1/3x= (x^2-2)/6x
5a/b^2-6a/b=(5a-6ab)/b^2

Answer 6

1) here ab is the LCM of ab and b....so the result is (5+3a)/ab.
2) here dr is LCM. so the result is (d-8)/dr
3) here x^2y^2 or (xy)^2 is the LCM. so te result is (2x+8y)/(xy)^2
4) here 6x is LCM..result: (x^2-2)/6x
5) here LCM is b^2..result: (5a-6ab)/b^2

Answer 7

5/ab + 3/b = 3/b +5/ab
then i think you carry the one and do the divisiodn (by zero) WATCH OUT FOR THE DIVZOR$END$$$

Answer 8

(5+3a)/ab
(d-8)/dr
(2x^2y+8x^2y)/x^3y^3
(x^2-2)/6x
(5a-6ba)/b^2

Answer 9

1)5/ab+3b
(5+3a)/ab

2)1/r-8/dr
(d-8)/dr

3)2/xy^2+8/x^2y
2(x+4y)/x^2y^2

4)x/6-1/3x
(x^2-2)/6x

5)5a/b^2-6a/b
a(5-6b)/b^2