2006-12-30 16:48:10 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Googolplex to the power of Googolplex
Googolplex ^ Googolplex
2006-12-30 16:51:18 · answer #1 · answered by Anonymous · 0⤊ 1⤋
Largest Real Number
2016-12-10 15:36:21 · answer #2 · answered by Anonymous · 0⤊ 0⤋
For the best answers, search on this site https://shorturl.im/awta5
There is no largest real number less than 10, because the set of real numbers is continuous. Note that 9.9999.... is equal to exactly 10, it's not less. 10 - epsilon is not a number per se. If there were a number 10 - epsilon that is the largest under 10, then you can always claim that 10 - epsilon/2 is even larger, and still under 10.
2016-04-08 07:33:49 · answer #3 · answered by Anonymous · 0⤊ 0⤋
By the cardinality of the continuum, the real number set has the cardinality of |R| or c. This means that there exists R|c being the largest real number in the real number set. Since googolplex is equivalently, 10^(10^100), so thus R|c > googolplex, that R|c is the largest real number bigger then googolplex.
http://en.wikipedia.org/wiki/Googolplex
http://en.wikipedia.org/wiki/Cardinality_of_the_continuum
2015-01-25 12:12:02 · answer #4 · answered by Anonymous · 0⤊ 0⤋
For HUGE numbers, check out Ackerman's Function: http://en.wikipedia.org/wiki/Ackermann_function. Even A(4,4) is ridiculously large, but A(googolplex, googolplex), forget about it!
2006-12-30 20:36:23 · answer #5 · answered by Phineas Bogg 6 · 0⤊ 0⤋
googolplexian: a 1 with a googolplex zeros.
2006-12-30 18:31:30 · answer #6 · answered by davieboy104 3 · 0⤊ 1⤋
infinity minus 1 over infinity
2006-12-30 17:01:37 · answer #7 · answered by Ivanhoe Fats 6 · 0⤊ 2⤋
Grahams Number.
It can be used in mathematical proofs.
2006-12-30 17:02:48 · answer #8 · answered by Som™ 6 · 4⤊ 0⤋
Infinity less one.
2006-12-30 16:50:05 · answer #9 · answered by Anonymous · 0⤊ 2⤋