x^2 - 5x + 6
__________
2x - 4
2006-12-30 16:36:41 · 7 answers · asked by jrrkidd 1 in Science & Mathematics ➔ Mathematics
Numerator factors using FOIL to:
(x - 2)(x - 3)
Denominator factors to:
2(x - 2)
Common factor is (x - 2), which can be eliminated, leaving:
(x - 3)/2
Note: no offense intended, but the purpose of this is for us to show you an example of how to do these, and then you do the rest on your own. Please try to do these on your own or you won't learn anything.
2006-12-30 16:38:38 · answer #1 · answered by Jim Burnell 6 · 2⤊ 0⤋
First: factor the numerator and denominator:
[(x-3)(x-2)]/2(x-2)
Second: cancel "like" terms > cancel x-2 >
(x-3)/2
2006-12-31 19:56:00 · answer #2 · answered by ♪♥Annie♥♪ 6 · 0⤊ 0⤋
x^2 - 5x + 6 can be rewritten as x^2-3x-2x+6,which further becomes x(x-3)-2(x-3), which becomes (x-2)(x-3)..
2x-4 becomes 2(x-2)
so finally,the answer is (x-3)/2
2006-12-31 00:47:27 · answer #3 · answered by Rajaram 1 · 1⤊ 0⤋
factor the top and factor a 2 out of the bottom.
then you have
(x - 3) (x - 2) / 2 (x - 2)
cancel the identical factors and you have (x - 3) / 2
2006-12-31 00:39:27 · answer #4 · answered by Shanny 2 · 1⤊ 0⤋
(x-3)(x-2)/2(x-2)
=(x-3)/2
2006-12-31 00:38:44 · answer #5 · answered by raj 7 · 1⤊ 0⤋
(x-2)(x-3)
________=
2(x-2)
(x-3)
________
2
I hope this helps!!
2006-12-31 00:40:54 · answer #6 · answered by smart-crazy 4 · 1⤊ 0⤋
gimme points
2006-12-31 01:02:52 · answer #7 · answered by koalabear 2 · 0⤊ 2⤋