2m^2 - 8m
_________
4m
2006-12-30 16:33:50 · 5 answers · asked by jrrkidd 1 in Science & Mathematics ➔ Mathematics
The numerator factors to:
2m(m - 4)
The denominator to:
4m
Common to both is 2m (since 4m = 2(2m)), so divide both by 2m, leaving:
(m - 4)/2
2006-12-30 16:36:40 · answer #1 · answered by Jim Burnell 6 · 1⤊ 0⤋
First: factor the numerator and denominator > find the least common factor >>>
[2m(m - 4)]/4m
Sec: cancel "like" terms > take 2m/4m and simplify>
[1(m - 4)]/2
(m - 4)/2
2006-12-31 20:03:31 · answer #2 · answered by ♪♥Annie♥♪ 6 · 0⤊ 0⤋
Again, factor first before you cancel out common factors. You cannot cancel the 4 on the bottom with the 8 on top. Here's how to do it...
On top, factor out the 2m .... (2m(m - 4))/4m
Next, cancel the 2m from top and bottom. This leaves
(m-4)/2
2006-12-31 00:40:36 · answer #3 · answered by Joni DaNerd 6 · 1⤊ 0⤋
start by factoring 2m from the numerator
2m^2-8m = 2m(m-4)
then factor 2m from the denominator
4m = 2m(2)
2m(m-4)
------------
2m(2)
cancel the 2m's from both
m-4
------ = 1/2m-2
2
2006-12-31 00:52:13 · answer #4 · answered by tval_friedly 2 · 1⤊ 0⤋
2m(m-4)/4m=(m-4)/2
2006-12-31 00:36:51 · answer #5 · answered by raj 7 · 1⤊ 0⤋