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A convex quadrilateral ABCD has its diagonals perpendicular to each other. The opposite sides AB and CD are not parallel. The perpendicular bisectors of AB and CD meet at P, which lies in the interior of ABCD. Prove that ABCD is cyclic only is triangles ABP and CDP have equal areas.

2006-12-30 16:28:59 · 1 answers · asked by Akilesh - Internet Undertaker 7 in Science & Mathematics Mathematics

1 answers

can u giv the figure..... then i can solve it..

2006-12-30 17:12:51 · answer #1 · answered by swapna 1 · 0 0

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