how would I graph the equation x-y=6 or y=f(x)=x^2?

Answer 1

You need to change the first equation into the slope-intercept form:
y=mx+b

Subtract x from both sides:
-y=-x+6

Divide -1 from both sides:
y=x-6

Just plug in numbers for x to get the y-values:
y=0-6
y=-6
(0,-6)

y=(0)^2
y=0
(0,0)

I hope this helps!

Answer 2

2

Answer 3

Easiest way is to make yourself a little table with two columns: one for x and one for y. Put a value in the x column and the associated value in the y column. Then graph the points and draw the line. The first one is simple because it's arithmetic. If x is 10, y is 4. If x is 2, then y is - 4. Plot the points and draw the line.

Answer 4

1. solve for y. plot y and x points between, say, x= - 4
and x = +10 (y on vertical axis as usual)

2. f(x) just is one way of saying: "y is a function of x". But y=x^2 defines y as a function of x so in this context it is redundant, probably just there to let you become familiar with translating it from mathspeak. plot y & x pairs between, say -4 an +4, as above.

You do know how to figure the y values, right?

Answer 5

an easy way of doing it for the x-y=6 type of equations is just to draw the points where the graph would cross the axes... so just chek what would be the value of "x" when "y" is zero, and viceversa and then draw the line.
for y=x^2 it's easy just by giving values to "x"

Answer 6

f(x)=x^2 is a parabola.give 6 values say to x and find the corresponding values of y and plot
x-y=6 is a line.putting x=0 and y=0 you get two points
passes through (0,-6) and (6,0) join.