A spot on the Earth has to make a 25000 mile circle in 24 hours at the equator but smaller circles as you move towards the poles. Since you are moving faster in Brazil than in Michigan, do you weigh less as the extra speed tends to pull you off the surface?
2006-12-30 15:53:50 · 12 answers · asked by Zefram 2 in Science & Mathematics ➔ Astronomy & Space
Yes a little bit, but you also weigh less at the equator because the spin makes the earth slightly flattened at the poles and slightly bulging at the equator, so you are further from the center of the earth and the force of gravity is less. According to a 1968 textbook I am just rereading, the total difference of centrifugal and distance from center is 0.5% from North Pole to Equator their example being a 1000 kg polar bear from the NP would weigh 995 at the Equator and spin force is 0.33%
2006-12-30 16:06:06 · answer #1 · answered by Mike1942f 7 · 3⤊ 0⤋
Gravity is basically the attraction of two masses. The larger the mass the larger the attraction, and the closer to the object the greater the pull. Gravity is not due to the earths rotation but is actually the attraction between your body and the earth. The earth is a very large object and thus the gravity force is high. And yes if you were on the top of Mt Everest you would technically weigh less, as if you were 50 KM from the earths surface you would also weigh even less. In space you are weightless as you are far away from the gravational pull of a planet.
Also note that the guys that walked on the moon did have some gravity to work with, but as the moon is much smaller than the earth, their weight is much less there.
Gravity is a force of attraction only between bodies that have mass. The word 'gravity' comes from the Latin word "gravitas", meaning 'weight'. The force of gravity that one body exerts on another can be expressed as:
Fgravity = G * m1 * m2/ r2
F = Force of gravity experienced by bodies. m1 = mass of body.
G = Gravitational constant , 6.6726 * 10-11 m3 kg-1 s-2. m2 = mass of second body.
r = radius of body.
Knowing the gravitational constant, the mass of the Earth, and your distance
from the centre of the Earth, you can work out the gravity of Earth.
Please note: Gravity is measured in Newtons(N) or kg m s-1.
2006-12-30 16:16:41 · answer #2 · answered by Derek E 2 · 0⤊ 0⤋
Yes, the person at the equatorial region will weigh less compared to the region at poles.
But, it is not due to the spin but due to the gravitational force of our earth on our body. How?
All bodies, whether living or non living beings, are attracted towards the centre of the earth by earth' gravitational force. The force is radial and not lateral.
Weight is nothing but the gravitational force exerted on the bodies by the earth. So, weight (gravitational force) of the body is the product of 'mass of the body' and 'the gravitational force exerted by the gravity on the body'.
Mass of a person does not change when moved from equatorial region to the pole, but the gravitational force differs.
It has been found that the gravitational force is maximum at the poles, since, geometrically, they are closer to the centre of the earth. Whereas, it is lesser at the equatorial region since it is at the farthest distance from the centre of the earth.
As we move up, like climbing on mount Everest, the gravitational force of attraction gradually decreases. So, the same body will weigh lesser and lesser as we go farther and farther from the centre of the earth.
2006-12-30 16:16:13 · answer #3 · answered by Shooting stars 3 · 0⤊ 0⤋
Gravity is gravity. Your weight won't replace. and you progression swifter on the equator. The circumference of the equator is larger then that of the “north pole”. for this reason you're in essence travelling added in the process a similar term. To coach this, have you ever and a chum bypass to a working song. one in each and every of you're taking the scoop, whilst the different is interior the a tactics exterior song. start up status completely aligned with one yet another. Slowly march your way around the song step for step. on the grounds which you traveled a similar velocity the guy on the exterior song would be in the back of the guy on the scoop while they attain the end. try this lower back this time allowing the guy on the exterior to stroll as speedy as needed to maintain up. You’ll the two end on a similar time.
2016-10-19 06:25:10 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Yes. The rotational acceleration, and the greater radius of the earth at the equator, combine to create a slight difference.
2006-12-30 16:21:06 · answer #5 · answered by Anonymous · 0⤊ 0⤋
yes!
@ the equator, your weight is reduced (compared to a non-spinning Earth) by about 0.3%; the effect weakens as you go north or south, and once you reach the north or south pole it disappears completely because theearth is not spinning there.
people's weight naturally fluctuates more than 0.3%, so it's unlikely that you'd be able to notice this from other effects
2006-12-30 16:08:00 · answer #6 · answered by Tharu 3 · 2⤊ 0⤋
yes we weigh less at equator due to the earth's spin
2006-12-30 17:54:40 · answer #7 · answered by Anonymous · 0⤊ 0⤋
you are thinking as to the latitudinal distance,...
weight is a function of the distance between the center of mass of the two objects.
so equitorial or polar distanmce is not a factor... only of elivation.
*You weigh less up on Mt Everest than you do at the Dead Sea.
2006-12-30 15:57:53 · answer #8 · answered by beanie_boy_007 3 · 0⤊ 1⤋
Yes you do because of spin
2006-12-30 16:17:56 · answer #9 · answered by Sak 2 · 0⤊ 0⤋
Yes, but it would only be a small amount less.
2006-12-30 16:09:02 · answer #10 · answered by I don't think so 5 · 0⤊ 0⤋