the colts are falling apart; how far will they go in the playoffs?
2006-12-30 15:07:43 · 12 answers · asked by XFactor 2 in Sports ➔ Football (American)
They will lose the first playoff game.... you are right they are falling apart. You can't win a game without a defense.
2006-12-30 15:16:35 · answer #1 · answered by kittycat lover 3 · 0⤊ 0⤋
They will not get very far in the play offs. They will not win the division, and I do not see a Super Bowl in their future. The team is not winning by large numbers when they do win, it is only usually just a few points. They get these wins when the other team makes mistakes that help them get there. The Colts are not consistent in their playing to get them to the big win.
2006-12-30 23:18:21 · answer #2 · answered by H 1 · 0⤊ 0⤋
As far as the first playoff team with a running game, and no farther.
2006-12-30 23:35:01 · answer #3 · answered by Anonymous · 0⤊ 0⤋
they will lose their first game. you need a good defense to win playoff games and they have one of the worst run defenses in the history of the nfl for the last 20 years
2006-12-31 00:31:41 · answer #4 · answered by Kev C 4 · 0⤊ 0⤋
Not far, many weapons but no run game...2nd round of playoffs
2006-12-30 23:20:44 · answer #5 · answered by howardlee1977 4 · 0⤊ 0⤋
they wont go far at all! i doubt if they get past the first round b/c they have the offense but their defense isnt reliable and from watching thier past few games they are not ready. The chargers r goin all the way wit LT as MVP
2006-12-30 23:17:52 · answer #6 · answered by A to the T 2 · 0⤊ 0⤋
THEY WILL GO TO THE PLAYOFFS AND LOSE THERE FIRST GAME AND GO HOME!
2006-12-31 01:06:19 · answer #7 · answered by Anonymous · 0⤊ 0⤋
I still think they will get to the AFC Championship game.
2006-12-31 00:15:39 · answer #8 · answered by WestCoastin4Life 7 · 0⤊ 0⤋
not far... maybe win first round, esp if they play Denver... that is about it
2006-12-31 00:08:57 · answer #9 · answered by dff701 2 · 0⤊ 0⤋
lose their 1st game
2006-12-30 23:10:31 · answer #10 · answered by Brad C 2 · 0⤊ 0⤋