2006-12-30 14:00:34 · 12 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x² - 16x + 64
(x -8)(x-8)
(x-8)²
2006-12-30 14:35:35 · answer #1 · answered by M. Abuhelwa 5 · 0⤊ 0⤋
They are x-8 and x-8. In other words, x²-16x+64 = (x-8)².
2006-12-30 14:26:16 · answer #2 · answered by steiner1745 7 · 0⤊ 0⤋
x-8
2006-12-30 19:46:22 · answer #3 · answered by Nitin T F1 fan 5 · 0⤊ 0⤋
x^2 - 16x + 64
= x^2 - 8x - 8x + 64
= x(x-8) - 8(x -8)
= (x-8)(x-8)
= (x-8)^2
2006-12-30 14:04:34 · answer #4 · answered by purpicita_LM_es_fg_MDK 2 · 0⤊ 0⤋
X=8 OR (X-8) but its the same thing
2006-12-30 14:08:45 · answer #5 · answered by Gigi 1 · 0⤊ 0⤋
That would be correct (X-8)^2
2006-12-30 14:05:26 · answer #6 · answered by ddjohjr 1 · 0⤊ 0⤋
(x-8)^2
2006-12-30 14:03:27 · answer #7 · answered by airtime 3 · 0⤊ 0⤋
(x-8)(x-8) or
(x-8)^2
2006-12-30 14:26:12 · answer #8 · answered by Anonymous · 0⤊ 0⤋
(x-8)^2
2006-12-30 14:16:31 · answer #9 · answered by Ojo 2 · 0⤊ 0⤋
(x-8)^2
2006-12-30 14:02:45 · answer #10 · answered by 7 · 0⤊ 0⤋