what is the domain of the function f(x)= log8(x-2)?
the choices are
A) integers > 8
B) real numbers > 0
C) real numbers >2
D) real numbers >-2
2006-12-30 12:46:59 · 7 answers · asked by Sam M 1 in Science & Mathematics ➔ Mathematics
C
because x-2 > 0
2006-12-30 12:49:38 · answer #1 · answered by feanor 7 · 0⤊ 1⤋
c
any logorythmic function has a domain of all real numbers greater than zero, the x-2 moves the domain 2 unites to the right.
2006-12-30 12:50:08 · answer #2 · answered by Dashes 6 · 0⤊ 0⤋
It's C) real numbers > 2. The argument of a
logarithmic function must be positive to get
a real output.
2006-12-30 13:03:11 · answer #3 · answered by steiner1745 7 · 0⤊ 0⤋
C. All real numbers >2 because you can't have a negative
8 to whatever power could never be a negative.
2006-12-30 12:51:38 · answer #4 · answered by Lilovacookedrice 3 · 0⤊ 0⤋
f(x)= log8(x-2) is equivalent to
x-2 = 8^f(x) > 0
Therefore, x > 2.
C is the answer.
2006-12-30 12:57:27 · answer #5 · answered by sahsjing 7 · 0⤊ 0⤋
I don't know but try looking for a math website.
2006-12-30 12:49:49 · answer #6 · answered by Stacy V 1 · 0⤊ 1⤋
C
2006-12-30 19:53:39 · answer #7 · answered by Nitin T F1 fan 5 · 0⤊ 0⤋