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Mr. Hill drives to toronto. One fay his average speed going to work was 80km/h but returning it was only 70km/h. If his total travelling time that day was 3 hours, how far from toronto is his home?

2006-12-30 10:59:23 · 5 answers · asked by Cutie 4 in Science & Mathematics Mathematics

5 answers

Let x be the time it drives to work, then the time to drive home is
3-x.
The distance is the same to work and back from work so
80x = 70(3-x)
80x = 210-70x
150x=210
x=1.4
The distance is 80x= 80*(1.4)= 112km

2006-12-30 12:30:34 · answer #1 · answered by CAM1122 3 · 1 0

80 x = time to travel to work
70 x = time to return

80x + 70x = 3 hours

150 x = 3 hours (180 min)
x = 180/150 = 1.2 min

80 x 1.2 = 96 k
70 x 1.2 = 94 k

total = 180 k

this is return trip mileage

therefore divide 180 by 2 = 90 k from toronto

2006-12-31 00:21:35 · answer #2 · answered by David C 2 · 0 0

Let t be driving time to toronto, then 3-t is the returning time.

Balance by the one-way distance d:

80t = 70(3-t) = d

t = 1.4 hr

d = 80t = 112 km

2006-12-30 20:48:26 · answer #3 · answered by sahsjing 7 · 0 0

adv. speed 75 x 3hr= 225

2006-12-30 20:25:21 · answer #4 · answered by Captgoody 2 · 0 1

omg that is diff sorry cant help

2006-12-30 19:01:40 · answer #5 · answered by Princess Cheerleader 1 · 0 1

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