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A) transferred to ADP, forming ATP
B) transferred direclty to ATP
C) retained in the pyruvate
D) stored in the NADH produced
E) used to phosphorylate fructose to form fructose-6-phosphate

2006-12-30 08:50:23 · 5 answers · asked by Anonymous in Science & Mathematics Biology

5 answers

Glycolysis itself converts 2 ADPs to ATPs net, while the citric acid cycle (TCA) / electron transport chain converts about 30 ADPs, so the answer is clearly not A (or B: how exactly do you transfer energy to an already fully-charged ATP?)
For D: the TCA produces more NADH's than glycolysis, so it's unlikely to be D. As for E: F-6-P is an intermediate in glycolysis, and its phosphorylation only requires either 1 or 2 ATP (I forget), compared to about 30 ATPs at the end. So I believe the answer is C: so much more energy is stored in pyruvate to yield 30 ATPs later in the TCA and electron transport chain. Hope this helps.

2006-12-30 10:37:17 · answer #1 · answered by Telodrift 2 · 0 0

Hmmm- I would say C
because:
A) only 2 molecules of ATP are formed by glycolysis
B) energy would be transferred to ADP, forming ATP
D) NADH is mostly produced in the Kreb's Cycle
E) nope

2006-12-30 09:28:42 · answer #2 · answered by Anonymous · 1 0

Well pyruvate retains more of the energy since the pyruvate moves on to the krebs cycle where more atp FADH2 and NADH is produced

2006-12-30 10:46:32 · answer #3 · answered by gordon_benbow 4 · 0 0

It's retained in pyruvate.

2016-05-22 21:47:40 · answer #4 · answered by Anonymous · 1 0

she is right. c is correct.

2006-12-30 10:34:53 · answer #5 · answered by willy 2 · 0 1

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