A projectile fired vertically upward rises 15,840 ft in the first second, 15,808 ft during the following second, and 15,776 ft the third second. How many feet does it rise the 45th second?
2006-12-30 08:19:47 · 4 answers · asked by Lawanna D 1 in Science & Mathematics ➔ Mathematics
on every floor, a projectile fire lowers 32 so on the 4th one, it would be 15,734 because on the 3rd one it was 15,776 and if u subtract 32 then the answer would be 15,734 , if u keep on subtracting , then you will find the answer.
2006-12-30 08:29:15 · answer #1 · answered by Angel 2 · 0⤊ 1⤋
Lawanna;
I had students in my remedial math class at a state university who got all the way through high school by having others do their work. Several of the students that I flunked had to leave the school and go to community college.
You are doing yourself a disservice to cheat so much. With a name like 'Lawanna' it suggests that you expect affirmative action to help you. It won't always.
2006-12-30 16:59:58 · answer #2 · answered by modulo_function 7 · 0⤊ 0⤋
d=Vot-.5at^2
15840=Vo-.5a
15808+15840=2Vo-2a
31648=2Vo-2a
15824=Vo-a
15840=Vo-.5a subtract
-16=-.5a
a=32ft/s^2
15840=Vo-.5a
15840=Vo-16
Vo=15856ft/sec
after 44 sec, the speed is 15840-32*44=14432ft,sec
in the 45th sec
d=14432*1-16*1^2
d=14416 ft
at the end of 45 sec
d=15856*45-16*45^2=713520-32400=681120ft or 129 miles
Vo is about mach 14.4 so I don't think this is very likely.
2006-12-30 16:35:08 · answer #3 · answered by yupchagee 7 · 0⤊ 1⤋
15840-15808=32
15808-15776=32
15776-32=15744
2006-12-30 16:31:15 · answer #4 · answered by OK 3 · 0⤊ 0⤋