factor 6x^2+x-15?

Answer 1

6x^2+x-15
= 6x^2-9x+10x-15?
=3x(2x-3)+5(2x-3)
=(2x-3)(3x+5)

Answer 2

I got a good trick for factoring trinomials with lead coefficient other than 1, saves you a lot of trial and error. just a minute and I'll get it for you...
Make a 4 by four box with positions for four numbers in it, like this:
|,,,,,,,, ,,,,,,,,,,|
|........ ..........|

In the top row, put the factors of the first term, that is, factors of 6x^2. Let's try 3 and 2, because they are close to each other and the middle coeffieicnt is small. (If the middle coeffieicnt was larger you'd need to multiply and add larger numbers to get it and then you'd try the 6 and 1)
| 3...2 |
| ... ... |
In the bottom row, put the factors of the last term, that is, 15. Use 5 and 3 rather than 15 and 1 for the same reasons as you use 3 and 2 in the previous step. Here's where you have to work in the signs. Since 15 is negative,
you'll need a + and a - because + * - = -.
[ 3 2 |
| 5 -3 |
Now multiply down the diagonals, add the results, and hopefully you shouold get the middle number. here,
(3 x (-3)) + (2 x 5) = -9 + 10 = 1.
This, 1, is the coefficient on the middle term so you know you got it right.
Finally, read the coefficients fom the columns
(3x + 5)(2x - 3) (I know some people might have said (2x - 3)(3x + 5), that's ok to, since multiplication is commutative)
Now, suppose you had put the 5 and -3 in the bottom row in the opposite order? Then they wouldn't add up to 1. (try it!) and you'd know that you need to rearrange them. that's why I recommend doing this with a pencil rather than a pen. So there's still a certain amount of trial and error involved but not near as much as before.

Answer 3

First: multiply the first coefficient by the last coefficient
(6)(-15) = 90. Find two numbers that give you 90 when multiplied and 1 (middle coefficient) by adding/subtracting. The numbers are: 10, -9 > rewrite the expression:

6x^2 + 10x - 9x - 15

Second: group "like" terms and factor both sets of parenthesis:

(6x^2 + 10x) - (9x - 15)

2x(3x + 5) - 3(3x + 5)

(3x + 5)(2x - 3)

Answer 4

6x^2+x-15
=(3x+5)(2x-3)

Answer 5

6x2 - 27x - 15 3(2x^2-9x-5) in case you do not see it use the quadratic equation extremely 2x^2-9x-5 b^2-4ac 80 one+40 121 +/-11 relax of q.f. (-b+/-11)/2a (9+/-11)/4 20/4, -2/4 5, -a million/2 x=5 x-5=0 (x-5) x= -a million/2 2x= -a million 2x+a million=0 (2x+a million) 3(2x+a million)(x-5) tell your acquaintances

Answer 6

6x²+x-15 = (3x+5)(2x-3)

Answer 7

(3x + 5)(2x - 3)

Answer 8

(2x-3)(3x+5)

Answer 9

(2x-3)(3x+5)