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I think I worded this properly. I was a chemistry lab assistant for three years.

2006-12-30 01:37:06 · 3 answers · asked by Phillip 4 in Science & Mathematics Chemistry

3 answers

Uranium is found in 3 forms---U234,U235 and U238
U235 uedergoes fisson with slow neutrons,those neutrons join the neuclous of U238 to form Neptunium,which in turn decays by beta enission to form plutonium.

2006-12-30 01:44:52 · answer #1 · answered by Anonymous · 1 2

Which uranium isotope?
Are you asking about the RATE of the decay of uranium (that would be first order)
Are you asking about the order of daughter products from the decay? U-235 ultimately decays into Pb-207 (known as the actinium or 4n +3 series). U-238 ultimately decays into Pb-206 (known as the uranium or 4n+2 series).

If you want to know the decay paths (there are several) do a google search for the these two series and you can get the details.

2006-12-30 13:52:25 · answer #2 · answered by The Old Professor 5 · 0 0

According to your wording:

ANY RADIOACTIVE DECAY PROCESS IS OF THE FIRST ORDER ONLY. Even that of Uranium.


About DECAY Series:
And U235 belongs to the Actinium series
U238 belongs to the Radium series

2006-12-30 10:00:55 · answer #3 · answered by Som™ 6 · 0 0

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