2006-12-29 17:40:28 · 5 answers · asked by yo yo ma 2 in Science & Mathematics ➔ Mathematics
i meant cos squared x... sorry
2006-12-30 05:46:23 · update #1
which is still not 0... i think it's -2cos2xsin2x
the the 2 means squared...
2006-12-30 05:50:54 · update #2
y = cos2x
First derivative taken with respect to x is
y' = -2sin2x
Second derivative taken with respect to x is
y'' = -4cos2x
Second derivative is 0 when:
-4cos2x = 0
cos2x = 0
2x = (Pi/2) + (Pi*k) where k is an integer
x = (Pi/4) + ((Pi/2)*k) where k is an integer
2006-12-29 17:49:47 · answer #1 · answered by alsh 3 · 1⤊ 0⤋
first AND 2d by-fabricated from y=cos2x dy/dx = d/dx(cos2x) = -2sin(2x) d^2y/dx^2 = d^2/dx^2 (-2sin(2x)) = -4cos2x d/dx (sqrt(x^2 +a million) ) = (a million/2)/ sqrt(x^2 +a million) (2x) = x / sqrt(x^2 +a million)
2016-11-25 00:20:34 · answer #2 · answered by ? 4 · 0⤊ 0⤋
no. Chain rule.
y' = -sin2x * (2x)' = -2sin2x
y'' = -2sin2x * (2x)' = -4cos2x
2006-12-29 17:43:48 · answer #3 · answered by Jim Burnell 6 · 1⤊ 0⤋
nope its 69y
2006-12-29 17:42:39 · answer #4 · answered by Dink 3 · 0⤊ 1⤋
no
2006-12-29 17:44:32 · answer #5 · answered by farzan 1 · 0⤊ 0⤋