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the given are only Rc of 10 kilo ohms and the supply voltage of 5 volts...there is no value of Rb..how can I solve it?please help..thanks in advance..!

2006-12-29 13:29:16 · 4 answers · asked by honeymay 2 in Science & Mathematics Engineering

4 answers

The collector current would depend on what voltage is across the transistor. Is it fully on or partially on? You need more information. If fully on then the current would be about 5Volts/10kOhms = 0.5mAmp Then to figure the required base current for fully on or some other current you would need the gain (beta) of the transistor. For example if the gain was about 100 then the base current would be 0.5mAmp / 100 or about 5uAmps. Your problem does not have enough information.

2006-12-29 13:34:06 · answer #1 · answered by rscanner 6 · 0 0

There is not much info given for an accurate answer, however I will assume some things and give you an answer based on that.

I'll assume its a self biased NPN transistor where the collector is connected to the base, this will mean that there is now 5 Volts appearing at the base.

Assuming this then and the emitter at ground....

The potential at the collector is 5Volts minus 0.6 volt drop across emitter base junction, minus 0.6 volt drop across base collector junction which equals 3.8 Volts... which means that the 10K collector resistor is dropping 3.8 Volts therefore the 10K resistor is drawing 3.8 micro Amps which is then the Collector Current.

The Emitter current equals the Collector Current so is 3.8 micro Amps as well. Collector current equals Emitter current plus Base Current, and as emitter current equals collector current in this case the Base current is considered to be zero.

I hope this helps

2006-12-29 20:27:43 · answer #2 · answered by Gaz 5 · 0 0

you ought to use a latch to hold the recommendations till cleared. or you ought to use a cap in some way. in all probability by potential of potential of way of a 555 timer IC. in case you in basic terms p.c. to be attentive to "how do I discharge a capacitor applying an NPN transistor", you ought to located a resistor in sequence, between the cap and the transistor collector to cut back the present to a cost that may no longer burn out the transistor. yet i do no longer think of of it particularly is the thank you to go.

2016-12-31 06:37:14 · answer #3 · answered by Anonymous · 0 0

First of all, what kind of configuration is it? Common base or common emitter?

What's the input side?

Assuming there is ZERO input, and assuming it is a common emitter, when there is no input, there is no collector current. If there is no input, there is no base current.

If this is truly the only information you have, you have a trick question. The answer is ZERO for both.

2006-12-29 13:39:13 · answer #4 · answered by tkquestion 7 · 0 0

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