40% alcohol content.
40% ABV.
All means the same thing. 40% on the content in the bottle is alcohol.
80% proof is the American way.
2006-12-28 16:33:00
·
answer #1
·
answered by protos2222222 6
·
0⤊
0⤋
Alcoholic proof is a measure of how much ethanol is in an alcoholic beverage, and is approximately twice the percentage of alcohol by volume (ABV, the unit that is commonly used at present).
In the definition current in the United States, the proof number is twice the percentage of the alcohol content measured by volume at a temperature of 60 °F (15.5 °C). Therefore "80 proof" is 40% alcohol by volume (most of the other 60% is water), and pure alcohol would be "200 proof". If a 150-proof beverage is mixed half-and-half with water, the product is 75 proof. US proof numbers are properly cited as, for instance, "86 proof," not "86 degrees proof." The use of the word "degrees" in this context is incorrect.
US Federal regulation (CFR 27 5.37 Alcohol Content) requires that liquor labels state the percentage alcohol by volume (sometimes abbreviated ABV). The regulations permit (but do not require) a statement of the proof as long as it is right next to the percentage alcohol by volume.
2006-12-29 03:42:51
·
answer #2
·
answered by MAK 1
·
0⤊
0⤋
Proof is double the percent of alcohol by volume. So, 80 proof is 40% alcohol, 90 proof is 45%, ect.
2006-12-29 00:37:01
·
answer #3
·
answered by zaleonia1 4
·
0⤊
0⤋
80 proof equals 40% alcohol
50% alcohol = 100 proof.
Simple math
Bacardi 151 = 75.5% alcohol
2006-12-29 00:37:36
·
answer #4
·
answered by Iceplayr 4
·
0⤊
0⤋
80 proof is some good **** that is what it is it is all good
2006-12-29 00:37:40
·
answer #5
·
answered by marie 2
·
0⤊
0⤋
It means its 40% alcohol.
The proof is always double the percentage.
Bottoms up :)
2006-12-29 00:39:17
·
answer #6
·
answered by JenJen 2
·
0⤊
0⤋
The amount of alcohol out of 100% that is in a bottle. Also very yummy!
2006-12-29 00:39:03
·
answer #7
·
answered by l'il mama 5
·
0⤊
1⤋
40% alcohol.
2007-01-01 01:45:09
·
answer #8
·
answered by Pinhead 2
·
0⤊
0⤋