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2006-12-22 01:08:16 · 5 answers · asked by Anonymous in Science & Mathematics Engineering

5 answers

Here you go and don't forget to add the filter

http://en.wikipedia.org/wiki/Rectifier

2006-12-22 01:13:49 · answer #1 · answered by Gene 7 · 0 0

You can obtain a full wave rectifier or make one with 4 diodes.
There are two inputs,usually marked a/c or with a little sine wave.
There are two outputs one marked positive and one marked negative.
Use a transformer on the a/c inputs,you will get a ripple output from the between minus and plus.Take a 1000 mfd electrolytic capacitor[25 volts d/c] and bridge the pos and neg.[the cap has pos and neg indicaters]
You will now have a d/c voltage of a certain value.
To make it useful a voltage regulator is required. You will have to select the voltage you need. The regulated output must be 6 volts less than the unregulated output of the rect-cap voltage.

2006-12-22 01:34:02 · answer #2 · answered by Billy Butthead 7 · 0 0

Rectifier circuit has on the enter area a transformer (Xformer). The bridge sounds like a sq. ring. call the 4 corners (nodes) as a, b, c, d clockwise. linked to a & c are the Xformer secondary terminals . the load into which rectified cutting-edge feeds is linked between b & d. on the on the spot we are going to see the polarity of diodes no matter if 'ab' or 'ba', 'ab' exhibits cutting-edge bypass from a to b etc. at the same time as 'a' is going severe (+ve), cutting-edge flows in 'ab' course, flows with the help of the load returning at 'd', in course 'dc' and go back to Xformer secondary go back course at 'c'. pick image '>' to point the present course, from left to jot down. So now you recognize the ahead course of diodes should be >ab> & >dc> (reachable if I mark it dc>=da>. A filter out is mostly extra befor the load to remove the hum of furnish frequency, 60Hz in u . s . a .. As at the same time as 'a' is going severe, 'b' on load-area is going severe, so 'b' is the + of DC furnish of load. I had to do this with no circuit diagram. yet you'll benefit a lot in case you draw the circuit following the verbal instructions I gave, like marking a, b, c, d. finally, all this you receives from any favourite textual content. yet i imagine you're hooked to information superhighway.

2016-12-01 02:08:40 · answer #3 · answered by Anonymous · 0 0

When doing homework why not try Google or Wikipedia first? You will get the answers much quicker.

2006-12-22 01:17:38 · answer #4 · answered by Anonymous · 0 0

draw a primary of a transformer and then the secondary of a trasnformer... then place a diode on the upper part of one secondary terminal and invert the diode symbol and place it in another terminal... then join the two terminals then connect your load... add a filter stage brfore the load....

2006-12-22 01:16:30 · answer #5 · answered by vasanth 1 · 1 0

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