2006-12-21 13:56:59 · 12 answers · asked by Anonymous in Health ➔ Diet & Fitness
Weight ranges go based on weight, height, and what size frame you have. So no one here can answer that. To find a healthy weight go to the doctor and talk about your weight. He'll have the answers. And if you decide you should lose some then you two can talk about what your options are for doing it healthy.
2006-12-21 14:01:21 · answer #1 · answered by Jen 4 · 0⤊ 0⤋
NO! Don't worry about it. It all depends on height, and 150 is a perfectly ok weight to be at, unless you are 3 feet tall. If you are worried, start walking and stay under 2500 cals a day. But at your day, you are going to gain weight to help you grow- make sure you drink lots of milk! It can help you lose weight, and keep your bones healthy.
2006-12-21 14:00:15 · answer #2 · answered by frustratedB 3 · 0⤊ 0⤋
Depends on height. If 5'4 loose 20
2006-12-21 13:58:28 · answer #3 · answered by Anonymous · 0⤊ 1⤋
It depends on your height and bone structure. I've seen six foot guys that weighed 300lbs that looked good and I've seen six foot guys that weighted less that looked fat and some that looked like scarecrows.
2006-12-21 14:06:54 · answer #4 · answered by djm749 6 · 1⤊ 0⤋
not if you are around 5' 9"
2006-12-21 14:08:33 · answer #5 · answered by Anonymous · 0⤊ 0⤋
if u r 5' 6" or taller than no
2006-12-21 14:06:33 · answer #6 · answered by Lucky#11 3 · 0⤊ 0⤋
It depends on your height.
I'm 5'3 and if I weighed that much I would be considered overweight.
Eat healthy and exercise and you'll be fine.
2006-12-21 14:03:01 · answer #7 · answered by Blank 3 · 0⤊ 0⤋
it depends . are you 4 foot tall or 6 foot tall? how much muscle mass do you have? what is your BMI? what is your percentage of body fat?
2006-12-21 13:59:37 · answer #8 · answered by jimmy_d787@sbcglobal.net 1 · 0⤊ 0⤋
It depends on your height.
2006-12-21 14:30:51 · answer #9 · answered by Ashley S 3 · 0⤊ 0⤋
well, its slightly bad, but it also depends on your height.
2006-12-21 14:04:23 · answer #10 · answered by Pre lives on 5 · 0⤊ 0⤋