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(x^2) / [(x^2 + 1)(x^2 - 1)]

2006-12-20 18:23:04 · 2 answers · asked by David 2 in Science & Mathematics Mathematics

2 answers

In this case, what you have is an irreducible quadratic, and a regular factorable quadratic. Your first step would be to factor the factorable quadratic.

(x^2) / [(x^2 + 1)(x^2 - 1)]

(x^2)/[(x^2 + 1)(x - 1)(x + 1)]

Whenever you have an irreducible quadratic, you will have two constants in the form Ax + B in the denominator. That's the partial fractions decomposition.

(x^2)/[(x^2 + 1)(x - 1)(x + 1)] =

(Ax + B)/(x^2 + 1) + C/(x - 1) + D/(x + 1)

2006-12-20 18:28:55 · answer #1 · answered by Puggy 7 · 0 0

didn't people already answer your other partial fraction decomposition question?

anyway it's A/(x+1) + B/(x-1) + Cx+D/(x^2+1) + = (x^2)/[(x^2+1)(x^2-1)]

2006-12-21 02:27:54 · answer #2 · answered by gamefreak 3 · 0 0

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