(-1/sqrt3, sqrt2/sqrt3).
Please explain in lots of details...
2006-12-20 15:48:56 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Since x is negative and y is positive the angle is in the second quadrant.
sin θ = √⅔
θ = arcsin (√⅔) = 125.3°
2006-12-20 16:56:31 · answer #1 · answered by Northstar 7 · 0⤊ 0⤋
The x and y coordinates of the intersection (of the terminal side of your angle in standard position) with the unit circle respectively define the cosine and sine of your angle.
For your angle theta: cos theta = -1/sqrt3
sin theta = sqrt2/sqrt3
(Additionally notice (sin theta)^2 + (cos theta)^2 = 1
the Pythagorean theorem)
2006-12-20 16:36:36 · answer #2 · answered by answerING 6 · 0⤊ 0⤋
a million. because of the fact the x and y coordinates are the two destructive the attitude lies interior the third quadrant Now for something the wonderful element to do is draw a triangle, you be attentive to the adjacent element is two/3 and the different element is radical5/3. Now sparkling up for the hypotenuse with the Pythagorean Theorem hypotenuse^2 = (radical5/3)^2 + (2/3)^2 as quickly as you have all the standards you in basic terms would desire to plug them in ex. sin theta = opp/hyp cos theta = adj/hyp opp = -radical5/3 adj = -2/3 hyp = in spite of the fact that the hypotenuse is
2016-12-11 13:21:06 · answer #3 · answered by ? 4 · 0⤊ 0⤋
The definition of sin(theta) is the y coordinate of the point on the unit circle that the angle in standard position intersects. So, although we don't know what theta is, the sin(theta) is simply √2/√3
2006-12-20 15:55:36 · answer #4 · answered by grand_nanny 5 · 1⤊ 0⤋
71
2006-12-20 15:58:07 · answer #5 · answered by Anonymous · 0⤊ 1⤋