when slope and 1 point is given..... eqn can be formed by
(y-y1)=m(x-x1)
where m=slope=(3)
y1=y-intercept of point=(-2)
x1=x-intercept of point=(1)
putting values in eqn we get
(y+2)=3(x-1)
which yields to 3x-y=5..........equation for line
2006-12-20 15:48:48
·
answer #1
·
answered by i m gr8 3
·
0⤊
0⤋
Start with the definition equation
y = m x + b
m is the slope. To solve for b, we can use the point information. Substitute the specific y and x of the point:
-2 = 3 (1) + b
Add -3 to each side, and
-5 =b
So y = 3 x - 5
2006-12-20 15:51:03
·
answer #2
·
answered by cattbarf 7
·
1⤊
0⤋
y= 3x - 5 , start at the point (1, -2) and you know the slope is change in y divided by change in x. If it is 3 then that means you go up 3 units on the y axis for every increase in 1 on the x axis. Therefore if you go to the left the y-intercept would be (0, -5) and the slope is 3, so the equation is y = 3x - 5.
2006-12-20 15:46:43
·
answer #3
·
answered by Shawn M 1
·
1⤊
0⤋
1+2=3-X
2006-12-20 16:05:52
·
answer #4
·
answered by Anonymous
·
0⤊
1⤋
*Make sure you know the slope-intercept formula:
y = mx + b
First: take the slope (3), the point (1, -2) and place them into the slope-intercept formula:
-2 = 3(1) + b
-2 = 3 + b
Second: find the y-intercept represented as the variable "b" by keeping it on one side by itself: subtract 3 from both sides:
-2 - 3 = 3 - 3 + b
-5 = b; b = -5
Third: take the y-intercept (-5), the slope (3) and place them into the slope-intercept form as an equation:
y = 3x - 5
2006-12-20 17:07:55
·
answer #5
·
answered by ♪♥Annie♥♪ 6
·
0⤊
0⤋
Use the formula y = mx + b.
The slope, m, is 3. y = 3x + b.
Plug in the x- and y-coordinates to the equation. -2 = 3(1) + b.
-2 = 3 + b
b = -5
The equation is now y = 3x - 5 :)
2006-12-20 15:45:42
·
answer #6
·
answered by Anonymous :) 5
·
1⤊
0⤋
y= mx + c
m = slope = 3
y = 3x + c ..... as this goes thru (1,-2), this point should satisfy this equation.
So -2 = 3 + c ..... c = -5
So, the eqn of the line is y = 3x - 5
2006-12-20 15:47:23
·
answer #7
·
answered by Srinivas c 2
·
1⤊
0⤋
To write this into an equation, you must understand what makes up the equation.
To put it into y-intercept form, you use the equation y=mx+b
m=slope
x=x
b=y-intercept
In this problem the slope is 3, put that where m is
y=3x+b
To find the y-intercept, you look at the pair of coordinates, the y value (-2) is the y-intercept. Put this number where b is in the equation.
So your answer is y=3x-2
2006-12-20 15:44:47
·
answer #8
·
answered by chris 2
·
0⤊
2⤋
Given factors (x?,y?) and (x?,y?) on a line, slope m = (y?-y?) / (x?-x?) For (-a million,3) and (0,-2), slope m = (-2-3) / (0- -a million) = -5/a million = -5 y = -5x + b -2 = -5(0) + b b = -2 y = -5x - 2
2016-10-15 08:42:18
·
answer #9
·
answered by ? 4
·
0⤊
0⤋
y=mx+b
m=3
y=3x+b
-2=3(1)+b
-2=3+b
-5=b
equation y=3x-5
2006-12-20 15:50:02
·
answer #10
·
answered by Anonymous
·
1⤊
0⤋