2006-12-20 14:22:27 · 10 answers · asked by highchaparral2006 4 in Games & Recreation ➔ Video & Online Games
nope it will b a couple of months b4 it goes down
2006-12-20 14:28:54 · answer #1 · answered by nintendo8888 5 · 0⤊ 0⤋
No! don't listen to people claiming about the lost of price due to the lost of christmas urges. It's a mumbo jumbo when we talked about PS3.
Perhaps, after jan, you will start finding the PS3's prices go down on Ebay. But that ebay thing is already ridiculously expensive to begin with.
The original retail price of PS3 60 GB is 599.99 not 2000 dollars like the one sold at Ebay.
The PS3 price will probably go down in a year or 2 (2008 or 2009), similar to what happened to PS2. Remember?
2006-12-20 22:47:38 · answer #2 · answered by ram 4 · 0⤊ 0⤋
YES! Fortunately, after Christmas, a really hot toy's price will go down. It's because of the natural urge of Christmas presents.By the time it's after Christmas, the PS3 will go down. Don't wait too long though because there is always another holiday!
2006-12-20 22:26:31 · answer #3 · answered by AZL 2 · 0⤊ 0⤋
No, ps3 prices will go down next year(2008) by only $100.
2006-12-20 22:24:54 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Don't think so, it's already the cheapest blu-ray player. So i dont think they will lower the price . Maybe next Christmas.
2006-12-20 22:35:49 · answer #5 · answered by homegirl_2793 2 · 0⤊ 0⤋
No, But your chace of aquireing on by then will increase 10 fold.
2006-12-20 22:33:23 · answer #6 · answered by drunkendwarf4327 3 · 0⤊ 0⤋
I'm afraid not. Maybe before next Christmas.
2006-12-20 22:30:30 · answer #7 · answered by Mariposa 7 · 0⤊ 0⤋
yes. they are up because of christmas, they know they will be sold at any price, which they prefer higher. Supply and Demand you know.
2006-12-20 22:30:04 · answer #8 · answered by stargurl_5887 3 · 0⤊ 0⤋
no, once mayb after a yr when bluray is cheaper they will
2006-12-20 22:24:57 · answer #9 · answered by imputh 5 · 0⤊ 0⤋
of course not
2006-12-20 22:35:12 · answer #10 · answered by David 1 · 0⤊ 0⤋