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I have noticed a few other people who post school questions on here so I figured why not see if anyone can help me try to understand Pre-Cal. If you can please answer one of these questions or more.

Find the slant assymtope of the rational function:

f(x)=2x^3-x^2-22x-28/(x^2-3x-4)






find the vertical assymtopes for

f(x)=(5x-3)(x^2+2x-3)







find the horizontal assymtopes of th rational function

f(x)=7x/(x^2-5)

Thank You!!

2006-12-20 13:21:41 · 2 answers · asked by what_an_id2 1 in Education & Reference Teaching

2 answers

Divide numerator by denominato getting 2x+5 +R where r is the remainder and 2x +5 is the polynomial part. The slant asymptote is then y= 2x+5

x^2+2x-3= (x+3)(x-1)
Therefore vertical asymptotes occur at -3 and 1 since the denominator is 0 athese x values.

Horizontal asymptotes occur only when the degree of the numerator is the same as the degree of the denominator. Since the degree of the numerator is < degre of denominator, there are no horizontal asymptotes for this function

2006-12-21 02:51:19 · answer #1 · answered by ironduke8159 7 · 0 0

the answer is 1

2006-12-20 13:24:47 · answer #2 · answered by Anonymous · 0 0

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