To change 10.0 M solution of sulfuric acid a 5.0M solution....?

Question

To change a 10.0 M solution of sulfuric acid a 5.0M
solution, do I mix 25.0 ml of
the 10.0M with 25ml of water? Or what?

Answer 1

Yes, you would use equal amounts of water and 10 M H2SO4.

M1 V1 = M2 V2

10 M x 25 mL = 5 M x V2

250 / 5 = 50 mL total
that means the 25 mL of the 10 M acid and the rest (25 mL) of water.

Answer 2

the moles of H2SO4 in 25ml of 10M n = V * C = 10*0.025 = 0.25 mol
the volume of 5M solution V = n/C = 0.25 / 5 = 0.05 = 50ml
the volume of water added 50 - 25 = 25 ml

Answer 3

Volume of concentrated solution x Concentration of concentrated solution = Volume of diluted solution x Concentration of diluted solution

(Vc)(10.0 M) = (Vd)(5.0 M)

So if you want 50mL of 5.0 M, then yes, measure 25.0 mL of 10.0 M H2SO4 and dilute with 25.0 mL of water.