2006-12-20 13:01:45 · 7 answers · asked by Just 2 in Science & Mathematics ➔ Chemistry
One
2006-12-20 13:04:08 · answer #1 · answered by Questioner 3 · 0⤊ 0⤋
1
2006-12-20 21:04:28 · answer #2 · answered by ld 2 · 0⤊ 0⤋
There should be one Pb 2+ ion in the equation. Since the nitrate ion NO3 has an overall charge on of 1- you need to 2 nitrate ions to form an ionic compound with Pb. If I'm not mistaken the overall equation should look something like this:
2KI (aq) + Pb(NO3)2 (aq) --> PbI2 (s) + 2K(NO3) (aq)
2006-12-20 21:11:50 · answer #3 · answered by iamdaroot 2 · 0⤊ 0⤋
its only 1 -the 2 applys to the (NO3).
if the 2 was in front of the Pb(NO3) then their would be two of the Pb(NO3) so it would be Kl+ 2Pb(NO3)
But any ways the answer is theirs only 1
2006-12-20 21:05:57 · answer #4 · answered by wmshope 2 · 0⤊ 0⤋
KI +Pb(NO3)2 => PbI2 + 2KNO3
just one ion Pb2+
2006-12-20 21:34:03 · answer #5 · answered by James Chan 4 · 0⤊ 0⤋
only 1
2006-12-20 21:10:37 · answer #6 · answered by baller ali 1 · 0⤊ 0⤋
one the two at the end of the brackets is for the group in the brackets
2006-12-20 21:04:50 · answer #7 · answered by biotravis 1 · 0⤊ 0⤋