New york is suppose to get her own reality show "I love New York" I haven't really heard much about it since it was announced about a month ago...
2006-12-20 12:37:02
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answer #1
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answered by Anonymous
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On the reunion special, New York said that she would always love Flav, but she would have to love him as a very close friend and that it was time for her to move on and find the man of her dreams. Flav agreed that they are meant to be just good friends. That's what the new show is for...so NY can find that man of her dreams. Should make for fun entertainment!
2006-12-20 20:42:47
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answer #2
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answered by glitterkittyy 7
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New York is going to have her own show called I love New York where she tries to find true love. I don't know what man is so desperate that he has to go as low as New York but whatever.
2006-12-20 21:22:00
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answer #3
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answered by football chick 6
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Nothing happened with the two of them...he and Dee are still together and NY gets her own show, although for the life of me, I cannot imagine who would voluntarily TRY to be the winner of her reality show...not only do you have to put up with her mental problems, but you also have to put up with that obnoxious drag queen Mother of hers...
2006-12-20 21:31:58
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answer #4
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answered by kate 5
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I love to show tha show flavor of love 1 n 2
2006-12-20 20:58:11
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answer #5
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answered by Anonymous
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New York is coming out with her own show on the same network, called "I love New York". I guess its about her trying to find love.
2006-12-20 20:36:38
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answer #6
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answered by rae 1
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yeah like in january newyork will come out with a new show called i love newyork, she will be the main girl and 20 guys will try to make her fall in love with them, its a spin off of flavor of love,only newyork will be the star, the show is already filmed and everything, she is porbably hanging out and married with whoever won the show as we speak
2006-12-20 20:36:46
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answer #7
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answered by 100% Español 5
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im a HUGEEE fan of Falvor of Love (the show) but i was also wondering the same thing.
2006-12-20 20:36:11
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answer #8
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answered by Anonymous
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