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A chord is a line segment with both endpoints on the circle, which does not pass through the center of the circle and defines the arc(generally the shorter circumfrence of a divided circle).
And I still have a 'chord' 1470mm & at 735mm perpendicular 250mm to furthest edge of circle/arc - quick I gotta get back to tescos

2006-12-20 11:04:37 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

5 answers

northstar got the correct answer
in one

here we are working in mm
assume that we are working
in the minor segment/sector
of the circle

construction:
draw circle with centre O and
radius r to cut circle with chord at
points A and B,so AO and BO
are equal to r
let c=length of the chord =1470
draw a radial line through the
mid-point of chord AB to meet the
curve of the circle at D,cutting AB
at X
let XD=h=250 andOX=d=r-h
using pythagoras,
r^2=(1/2c)^2+(d)^2
r^2=(1/2c)^2+(r-250)^2
r^2=(1/4)*(1470)^2+(r-250)^2
r^2=(1/4)*(1470)^2+r^2-500r
+250^2
500r=(1470)^2/4+250^2
>>r=(1470)^2/2000+250/2
=1080.45+125=1205.45

hence,the radius of the
circle is 1205.45 mm

{note:you can check this answer
with the 'chord'rule
(2r-250)*(250)=735^2
this gives r=1205.45}

i hope that this helps

2006-12-20 23:54:39 · answer #1 · answered by Anonymous · 0 0

I submitted an answer on your first question. Look there. The problem people are having in understanding your question is not the definition of a chord. We know that. The problem is the phrase:

a 'chord' 1470mm & at 735mm perpendicular 250mm to furthest edge of circle/arc

What do you mean by that?

2006-12-20 11:11:24 · answer #2 · answered by Northstar 7 · 0 0

IWhen I draw the picture of what it seems that you're describing, it appears that your radius is 985, but that seems too simple and I'm probably wrong. Problem is, your question is not at all clear. Any way you could put up a picture in photobucket?

2006-12-20 11:11:18 · answer #3 · answered by Joni DaNerd 6 · 0 0

735 x 3.149

2006-12-21 01:12:57 · answer #4 · answered by Anonymous · 0 0

dunno....

2006-12-20 11:06:31 · answer #5 · answered by Anonymous · 0 1

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