Whats the radius of my circle ?

Question

I have a 'chord' 1470mm & at 735mm perpendicular 250mm to furthest edge of circle - help

Answer 1

1205mm (to nearest mm)
I too, was not very happy with the language of the question.
If you cannot express yourself precisely, it makes it very hard
to answer with confidence.
Have you considered a career in shelf stacking?

Answer 2

The question is unclear but I am guessing that a circle has a chord of 1470 mm. A radius of the circle thru the midpoint of the chord creates a sagitta of 250 mm. What is the radius?

Let

r = radius
c = chord = 1470 mm
a = apothem
s = sagitta = 250 mm

Using the Pythagorean Theorem

r^2 = a^2 + (c/2)^2 = a^2 + c^2 / 4
c^2 / 4 = r^2 - a^2
c^2 = 4(r^2 - a^2) = 4(r + a)(r - a)
c^2 = 4[r + (r - s)]s = 4(2r - s)s = 8rs - 4s^2
c^2 + 4s^2 = 8rs
8rs = c^2 + 4s^2
r = (c^2 + 4s^2) / 8s
r = (1470^2 + 4*250^2) / (8*250) = 1205.45 mm

Answer 3

northstar got the correct answer
in one

here we are working in mm
assume that we are working
in the minor segment/sector
of the circle

construction:
draw circle with centre O and
radius r to cut circle with chord at
points A and B,so AO and BO
are equal to r
let c=length of the chord =1470
draw a radial line through the
mid-point of chord AB to meet the
curve of the circle at D,cutting AB
at X and the major arc at F
let XD=h=250 andOX=d=r-h

using the chord rule
FX*XD=AX*XB
(r+OX)(h)=735^2
(r+(r-250))(250)=735^2
(2r-250)(250)=735^2
500r=735^2+250^2
r=(735^2+250^2)/500
>>>r=1205.45

hence,the radius of the
circle is 1205.45 mm

i hope that this helps

Answer 4

can you post the q exactly as it is inthe text book?

Answer 5

r=d/2
r=250/2
r=150mm

Answer 6

I don't understand your question

Answer 7

reword your question