In Inches:
50 centimeters = 19.6850394 in
60 centimeters = 23.6220472 in
In Feet:
50 centimeters = 1.64041995 feet
60 centimeters = 1.96850394 feet
Multiplied (50 x 60):
3,000 centimeters = 1,181.10236 in
3,000 centimeters = 98.4251969 feet
For future reference, go to google and type in "50 cm to in" to convert 50 centimeters into inches. The first result it gives you is the conversion. It also does it for weight, and even cups and ounces and whatever measurements you can come up with :)
2006-12-20 09:29:18
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answer #1
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answered by Vera 2
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This Site Might Help You.
RE:
Does anyone know how to convert cm to ft. 50x60 cm = how many feet/inches?
2015-08-13 19:21:50
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answer #2
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answered by Anonymous
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25.4 mm per inch, just do the math, metrics are set in 10's
1 foot = 12 x 25.4 = 304.8 mm = 30.48 cm
50 cm = 50 / 30.48 = 1.64 ft; 1 ft 7 2/3 in.
60 cm = 60 / 30.48 = 1.97 ft; 1 ft 11 16/35 in.
3000 cm = 3000 / 30.48 = 98.425 = 98 ft 5 1/10 in.
2006-12-20 09:47:54
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answer #3
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answered by honest abe 4
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It LOOKS like you have an area
(50 cm)*(60 cm) = 300 cm^2
(300 cm^2)(1 in/2.54 cm)(1 in/2.54 cm) = 46.5 in^2
(46.5 in^2)*(1 ft/12 in)*(1 ft/12 in) = 0.32292 ft^2
2006-12-20 09:58:51
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answer #4
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answered by Helmut 7
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There are 2.54 cm per inch, 30.48 cm per foot.
2006-12-20 09:26:59
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answer #5
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answered by Robbie 2
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if it is 50*60cm i.e. 3000 cm
it is equal to 3000/2.54 inch1181 in
=3000/(2.54*12) feet=98.42'
if itis 50cm*60cm=3000cm^2
=3000/(2.54)^2 sq.in.=465 sq.in
=3000/(2.54)^2(12)^2 sq.ft.=32.3 sq.ft.
2006-12-20 10:13:57
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answer #6
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answered by raj 7
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we know 1ft =12inches=2.54cm
For 50*60cm or 3000cm we got:
3000/2.54 =1181ft 1/10inch
2006-12-20 10:14:43
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answer #7
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answered by Johnny 2
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30.4 cm = 1 foot
2006-12-20 09:26:40
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answer #8
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answered by Anonymous
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demensional analysis
50cm 1 in 1ft 3.281 cm 164.05 ft
___ x ____ x _____ x _____ =________ =0.069 ft/in
60cm 3.281cm 12in 1 in 2362.32 in
(cm cancel out cm, in c/o in, and cm c/o cm )
2006-12-20 09:34:29
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answer #9
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answered by cartwrightfour4 2
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98.6842105.......... feet.
2006-12-20 09:29:09
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answer #10
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answered by Dmaista 2
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