2006-12-20 09:01:44 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
There's no easy way to do this one. You gotta multiply the whole thing out.
(x^2 - 2y)^3 = (x^2 - 2y)(x^2 - 2y)(x^2 - 2y)
multiply the first two, then multiply the result of that with the third. good luck!
2006-12-20 09:12:04 · answer #1 · answered by John C 4 · 0⤊ 0⤋
Since (a + b)³ = a³ + 3a²b + 3ab² + b³
(x² - 2y)³ = (x²)³ + 3(x²)²(-2y) + 3(x²)(-2y)² + (-2y)³
= x^6 - 6x^(4)y + 12x²y² - 8y³
2006-12-20 17:47:49 · answer #2 · answered by Wal C 6 · 0⤊ 0⤋
The answer is
(x^2 - 2y)^3 = x^6 - 6yx^4 +12x^2y^2 -8y^3
2006-12-20 17:10:44 · answer #3 · answered by wadie 1 · 0⤊ 0⤋
(x^2-2y)^3=
1 (x^2)^3 (-2y)^0
-3 (x^2)^2(-2y)^1
3 (x^2)^1(-2y)^2
-1 (x^2)^0(-2y)^3
=x^6
+6x^6 y
+12x^2. y^3
+8y^3
2006-12-20 17:14:31 · answer #4 · answered by iyiogrenci 6 · 0⤊ 0⤋
x^6-8y^3-6x^4y+12x^2y^2
2006-12-20 18:17:59 · answer #5 · answered by raj 7 · 0⤊ 0⤋