Help With Algebra?

Question

How do u do these...
Put in slop Form.

2x - 3y -9 = 0

3x + 2y +6 =0

2x - y=0

y =4

Answer 1

2x - 3y -9 = 0
-3y=-2x+9
y=(-2/-3)x+(9/-3)
y=(2/3)x-3

3x + 2y +6 =0
2y=-3x-6
y=(-3/2)x-3

2x - y=0
-y=-2x
y=2x

y =4
already in the reqd. form

Answer 2

1. You need to know the slope-intercept formula >>>
>>>> y = mx + b

First: add 9 to both sides because moving to the opposite side means opposite sign:

2x - 3y - 9 + 9
2x - 3y = 9

Second: subtract 2x from both sides:

2x - 2x - 3y = -2x + 9
-3y = -2x + 9

Third: solve for "y" and keeping it on one side > divide everything by -3 >>>

-3y/-3 = -2x/-3 + 9/-3
y = 2x/3 - 3

2. *Same format as number 1 >>>

First: subtract 6 from both sides:

3x + 2y + 6 - 6 = 0 - 6
3x + 2y = - 6

Second: subtract 3x from both sides:

3x - 3x + 2y = -3x - 6
2y = -3x - 6

Third: divide both sides by 2:

2y/2 = -3x/2 - 6/2
y = -3x/2 - 3

3. y = 4 is already in the slope-intercept form

Answer 3

Do you mean slope-intercept form? y=mx+b

Then solve for y in each of the equations.

2x-9=3y
divide by 3
(2/3)x-3=y

2y=-3x-6
divide by 2
y=(-3/2)x-3

y=2x

y=4

Answer 4

Slope form is y=mx+b

so first u have to isolate the y

-3y=-2x+9
***y=2/3x-3**** Theres the answer to #1
2y=-3x-6
***y=-3/2-3**** Theres #2
-y=-2x
***y=2x**** Thats #3
and #4 is already in proper form

Answer 5

2x-3y-9=0
+3y +3y
2x-9=3y
/3 /3
2/3x-3=y


3x+2y+6=0
-3x -3x
2y+6=-3x
-6 -6
2y=-3x-6
/2 /2
y=-3/2x-3


2x-y=0
-2x -2x
-y=-2x
y=2x

y=4

Answer 6

slope form is : y = mx +b where m is the slope and b is the y-intercept. Therefore all you need to do is to solve each of the equations for y. Hopefully you can do that. If not, slope form will be complicated for you.

Answer 7

y=2/3x-3, or in standard form, 2x-3y=9
thats the first one.

Answer 8

no