At East Zone University there are 449 students taking college algebra or calculus. 168 are taking college algebra, 342 are taking calculus, and 61 are taking both college algebra and calculus. How many are taking algebra but not calculus??????
It is multiple choice so here are there answers::
A) 46
B) 388
C) 107
D) 281
I have the answers, but I have no idea how to do this problem. Please show me your steps. Thanks a bunch!
2006-12-20 07:00:45 · 6 answers · asked by emmasahottie 3 in Science & Mathematics ➔ Mathematics
C) 107
If you wish to do this using Venn diagrams, you would have two intersecting circles. Call the one on the left Algebra students and the one on the right Calculus students. The intersection of the the two circles is the students taking both.
The total Algebra students is 168 (whole left circle). The students taking just algebra is the whole circle (168) minus the intersection (61) which is 107.
A quick check can be done by adding the number of students just taking Algebra (107) to the total number of students taking Calculus (with or without Algebra, which is 342):
107 + 342 = 449 which is the total number of students taking at least one of these math classes.
2006-12-20 07:07:20 · answer #1 · answered by Richard 7 · 15⤊ 0⤋
You said there are a total of 449 students.
168 are taking Algebra and 342 are taking calculus and 61 are taking both.
To find out the number of students taking only Algebra subtract it from the common term
so the answer is 168-61=107
Also apply the same rule to figure out students taking only Calculus
the answer is 342-61=281
To check whether your answer is right or wrong,add all
Students taking Algebra only = 107 +
Students taking Calculus only= 281 +
Students taking both = 61
-----------
Total number of students = 449
-----------
The answer for your question is C)107
2006-12-20 07:15:32 · answer #2 · answered by Eshwar 5 · 1⤊ 0⤋
Step 1: Make a Venn Diagram and write on the left Algebra(A).
Step 2: In the middle write b(both)
Step 3: Write c(calculus)
Step 4: Write the number of students taking just algebra.
168
- 61
_______
107 THE answer would be (C) 107
2006-12-20 07:57:09 · answer #3 · answered by COREY H 1 · 1⤊ 0⤋
The problem gives more information than is needed to solve the problem.
Let A= set of students taking college algebra
Let C= set of students taking calculus
Note that 168 are in A; this includes A intersection C.
There are 61 in (A intersection C).
The question asks for [A excepting (A intersection C)] = 168 -61.
Done!
2006-12-20 07:46:25 · answer #4 · answered by Jerry P 6 · 1⤊ 0⤋
A Venn diagram would be overkill here. The answer is practically given to you:
"168 are taking college algebra"
"61 are taking both college algebra and calculus"
Why do you think 168 are taking algebra, but only 61 are taking both courses? Why the difference?
And why does somebody think this is a wrong answer??!?
2006-12-20 07:04:03 · answer #5 · answered by Anonymous · 0⤊ 2⤋
you may ought to state the undertaking clearer. i'm not sure what the ninety 5's place is in any respect. in case you mean that the ninety 5 dislikes the two canines and cats, that should pass away one 0 five who like one or the different or the two. because fifty 9 cat likers + sixty 8 canines likers = 127 there must be some overlap. Subtract sixty 8 from one 0 five to get how many of the one 0 five are no longer cat likers: 37. through fact the one 0 five the two like cats or canines or the two, and those 37 of them do unlike cats, they ought to like canines. That bills for 37 canines likers and leaves fifty 9-37=22 canines likers who ought to additionally like cats. 22.
2016-10-15 07:56:37 · answer #6 · answered by ? 4 · 0⤊ 0⤋