The question i am having trouble with is this one.
A ship leaves port at noon and has a bearing of 117 degrees. If its speed is 15 knots, how many nautical miles south and east will the ship have traveled by 6:00 P.M?
The part i am having trouble with is the bearing. I dont know how to draw the picture and what angle to use for the traingle.
PLEASE ANSWER BACK ASAP THANK YOU
2006-12-20 06:53:47 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
I believe the bearing starts at 0° = North, and increases clockwise. So 90°, east, would corresponding to a mathematician's 0°, and 117° would correspond to -27° in the fourth quadrant.
2006-12-20 06:59:10 · answer #1 · answered by Anonymous · 0⤊ 1⤋
The "bearing", as you called it is actually azimuth which is measured clockwise from North. To convert this to a right triangle, you would use 27° for the angle from due east towards the South. Take the cosine of 27° and multiply times 90 nautical miles for the distance East and take the sine of 27° and multiply times 90 nautical miles to get the distance South.
2006-12-20 15:00:28 · answer #2 · answered by Anonymous · 0⤊ 0⤋
East = cos27=x/90
cos27x 90= 80.19 Nautical miles east
South= sin27=x/90
sin27x90=40.86 Nautical miles south
2006-12-20 15:34:21 · answer #3 · answered by Shmesh 3 · 0⤊ 0⤋