determine the volume of o hose of length 530cm.Whose inner radius is 5cm and outer radius 6cm.?

Question

this is the correct statement.
please i need your help.

Answer 1

If you mean the volume of hose material
=Pi[Ro-Ri]^2*L
=22/7[36-25]*530 cm^3
=22/7*11*530
=18322.857 cm^3

Answer 2

The hose we can assume is a ciynder so the volume is transversal area * lenght.
The Area of a circle is pi*r^2, like a hose is an annulus because of his two radius.
The area will be pi*(R^2-r^2) where "R" is the bigger radius and "r" the smallest one
if R = 6 cm and r = 5 cm the area will be:

A = pi*(6^2-5^2) = 34,6 cm^2

and the volume is V = A*L = 34,6*530 = 18338 cm^3

V = 18338 cm^3 will be the volume only of the hose.

if you want the inner volume of the hose, where the liquid pass, only use the inner radius r=5 cm

V = pi*r^2*L = pi*5^2*530 = 41626 cm^3

Answer 3

Volume = length * width * height
which is the same as length * area of the base of the object.
so in this case the length would be 530cm, the area (pi * radius squared) would be pi * (5cm)^2.
The area and length need to be multiplied together like the volume formula states.
This is
530cm * pi * 25 square cm
which equals 41,626 cubic cm

If the question is asking for the actual tubing volume (which I don't know why they would be asking that, although they did give you the amount of tubing) then it would be just pi * (6cm)^2 - pi * (5cm)^2
which equals 34.5 square cm
so then you use that for your area and still use the length as before.
That would be
530cm * 34.5 square cm
which equals
18,285 cubic cm

Answer 4

volume=pi(R+r)(R-r)*l
=3.14*11*1*530
=18306.2 cc