Need help with a chemistry experiment ==> MgSO4 added water to it, XH2O... How do I find what X is?

Question

what method or type of experiment do I need to do to fine how much water is in MgSO4 XH2O.

Answer 1

If the Magnesium sulfate is disolved in water and the water allowed to evaporate, then the most stable form of the product is Epsom Salt (Magnesium sulfate heptahydrate). X would be Seven.

To prove this experimentally, complete the following steps:

Record the mass of a sample of the original solid.

Transfer the solid to an evaporating dish and heat it for at least 15 to 20 minutes. Cool to room temperature and record the mass again.

Repeat the step above until the final mass remains constant.

The final mass is the mass of the anhydrous Magnesium sulfate. The difference of the final mass and the initial mass is the mass of water of hydration.

Calculate the moles of Water. Divide the mass of the water removed by the moleculer mass of water (18.0 g/mol).

Calculate the moles of Magnesium sulfate. Divide the mass of the final material by the formula mass of MgSO4 (120.4 g/mol).

Divide the number of moles of Water by the number of moles of MgSO4 and round to the nearest whole number. This is the number of moles of water of hydration in the initial material (X).

Answer 2

First weigh the sample. Next heat the sample until not further change in mass occurs. Re weigh the sample remaining. The difference is the mass of water removed. (First weight minus mass remaining).
Divide the mass of sample remaining by molar mass MgSO4= mols of MgSO4
Next divide the mass of water removed by molar mass H2O = mols of water.

Divide moles of water by mols of MgSO4 = X

Good luck

Answer 3

x must be 7 and its name is opossum salt and used in medicine

Answer 4

x is the average hydration value, between two or three...