the headlights will still move away from the car at the same speed, as the speed of light is relative.
2006-12-20 02:55:40
·
answer #1
·
answered by Polly 3
·
0⤊
0⤋
Your Car is moving at the speed of light and so are the headlights, so it will be normal for u , as u will see the light ahead of car, bcoz the speed of light coming from headlights will actually be equal to 2C ( c= speed of light)
another example is if a train is moving at a speed of 60 km/hr and u r travelling in it then ur speed is also equal to 60 km/hr.
2006-12-21 08:52:21
·
answer #2
·
answered by jasvinder 1
·
0⤊
0⤋
The car can't move as fast as the speed of light. It would violate the principles of special relativity. Regardless, whether the car is moving or standing still, the light from the car would travel at the speed of light, if it was in a vacum. Just like the light from the Sun travels at the speed of light, yet the Sun can be said to be still.
2006-12-20 12:37:29
·
answer #3
·
answered by G Constant 2
·
0⤊
0⤋
The speed of the headlights will be same as that of light that is 3*10^8 mt/sec
2006-12-20 10:59:08
·
answer #4
·
answered by mohd matheen 1
·
0⤊
0⤋
In order for this question to make sense from the point of view of Relativity, we'd have to have the car go at "almost" the speed of light.
For the driver, the photons of light would appear to shoot forward at the relative speed of 300,000 km/s (the speed of light). For a stationary observer, the photons would appear to go at 300,000 km/s, just a bit faster than the car.
If the car were going at exactly the speed of light, then time would not flow for the driver. She would not be able to turn on the headlights, as that action takes a finite time (i.e., more than zero) and that amount of time, however small, is not available to her.
2006-12-20 11:02:20
·
answer #5
·
answered by Raymond 7
·
1⤊
0⤋
If some mass goes the speed of light, it will have infinite mass.
m(final) = mass(initial) / sqrt(1 - (v^2/c^2))
you can see, when velocity is the same as the speed of light, then (v^2/c^2) will equal 1. Then 1 - 1 = 0. The square root of 0 is 0. Anything divided by zero is undefined. As the number approaches 0, the mass(initial) approaches infinity. The limit of this equation as v approaches the speed of light is infinity.
2006-12-20 11:45:23
·
answer #6
·
answered by Anonymous
·
0⤊
0⤋
The lights themselves will be traveling at the same speed as the car. The beam will also be going the speed of light, the same. If you were to look at it head on, you would see 2 lights approaching, but the light would not get there first. There would be no Doppler shift.
2006-12-20 10:58:49
·
answer #7
·
answered by science teacher 7
·
0⤊
0⤋
same as the speed of light
2006-12-20 11:10:55
·
answer #8
·
answered by Samarth 2
·
0⤊
0⤋
the driver or th erider will feel as if he is driving inside a sea of light.
because
let "c" be the velocity of light. the vel0ocity ofcar is also "c".
hence, relative velocity = c - c
=0
which shows that the rider will feel like sailing in a sea of light.
2006-12-20 11:02:36
·
answer #9
·
answered by Ankit B 4
·
0⤊
0⤋
the speed of light.
2006-12-20 10:59:21
·
answer #10
·
answered by Phillip W 2
·
0⤊
0⤋