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A water sample contains 0.0700 grams of arsenic in 10.0L of water. What is the concentration of the arsenic in

parts per million (ppm)?

2006-12-20 02:22:27 · 5 answers · asked by Anonymous in Science & Mathematics Chemistry

5 answers

Concentration of Arsenic =0.07/10 g/l
=0.007 g/l = 7 mg/l
1 milligram per litre (mg/L) is, loosely speaking, 1 ppm, for small concentrations in a water solution
=7 ppm

2006-12-20 02:26:25 · answer #1 · answered by Som™ 6 · 5 0

Parts per million (ppm) is as the name suggests, 1 part of mass, volume, etc, dissolved in 1,000,000 parts of mass, volume, etc.

Relation of units of mass / volume must be in a proportion of 1,000,000 one respect the other: For example, mg/L obey this rule, g/metric ton obey this rule, mg/Kg, mL/m³, etc obey this rule.

In your example,

0.0700 grams of arsenic in 10 Liters of water, you just have to convert the grames to miligrames:

0.07 grams x1000 = 70 miligrams

So you just apply:

70 mg/10 L = 7 mg/L = 7 ppm

Hope it was clear!

Good luck!

2006-12-20 02:32:51 · answer #2 · answered by CHESSLARUS 7 · 5 0

0.07 gr As dissolved in
10 liters water = 10000 gr of H2O
- - - - - - - - - - - - - --- - - - - - -
Calculations:

0.07 gram / 10 000 gram ;
multiply both by 100 to have 1000000;

(0.07 * 100) / ( 10000 * 100) = 7 / 1000000;

seven parts / one million parts ;

seven parts per million,; or 7ppm

easy , O.K.?

2006-12-20 02:45:09 · answer #3 · answered by istanbulengineer 2 · 6 0

(0.07g x 10g x 1000 ppm) / (10,000g x 0.01g) = 7 ppm

2006-12-20 17:43:54 · answer #4 · answered by Anonymous · 2 1

0.01g in 10g = 1000ppm

You can use this formulat to calculate ppm for any of your problem.

0.07 g in 10000 g of water = how many ppm?

(0.07g x 10g x 1000 ppm) / (10,000g x 0.01g) = 7 ppm

2006-12-20 03:32:06 · answer #5 · answered by pkababa 4 · 0 6

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