2006-12-20 02:17:40 · 17 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
+/-2i end.
2006-12-20 02:20:31 · answer #1 · answered by grassu a 3 · 1⤊ 0⤋
2
2006-12-24 02:03:13 · answer #2 · answered by blue angel 3 · 0⤊ 0⤋
If you're asking for the square root of -4, then you have no answer. It is impossible to have a square root of a negative number if you know how the squaring system works. You have to multiply a number by itself and it has to have the same sign (+ or -). Positive and positive get you another positive and negative and negative get you positive also (+*+=+, -*-=+). So you would need 2*-2 which doesn't work because it's not a squaring.
2006-12-24 06:37:50 · answer #3 · answered by sundar k 2 · 0⤊ 0⤋
If you're asking for the square root of -4, then you have no answer. It is impossible to have a square root of a negative number if you know how the squaring system works. You have to multiply a number by itself and it has to have the same sign (+ or -). Positive and positive get you another positive and negative and negative get you positive also (+*+=+, -*-=+). So you would need 2*-2 which doesn't work because it's not a squaring.
2006-12-20 10:24:06 · answer #4 · answered by Alcoli 1 · 0⤊ 1⤋
That would be + / - 2i
A great German mathematician by the name of C.F. Gauss invented the complex numbers because he felt that every polynomial equation should have a solution, whether you wind up having to take the sqrt of a negative or positve number. The tricky part was to get the complex numbers to behave properly according to the rules for arithmetic and algebra. When he accomplished this, it seemed there would be no practical application for his creation, so it was called "imaginary numbers". Later it was found that complex numbers are very useful in engineering.
2006-12-20 10:39:54 · answer #5 · answered by Joni DaNerd 6 · 0⤊ 0⤋
Root of -4 is 2i which is a complex number. It does not exist on Real Number line.
2006-12-20 11:11:34 · answer #6 · answered by Syed A 1 · 0⤊ 1⤋
root over 4 is root over 2 square that is square and root gets cancelled and remains only 2.
therefore root over 4 is 2.
2006-12-20 11:06:15 · answer #7 · answered by mohd matheen 1 · 0⤊ 1⤋
you need to do it using a complex number idea.
we know i= (1,0)
so, i^2 = -1
now
root(-4) = root (4*i^2)
=+- 2*i
=+/- 2i
2006-12-20 11:43:20 · answer #8 · answered by Ankit B 4 · 0⤊ 0⤋
root over4 is equal to 2
2006-12-20 11:34:14 · answer #9 · answered by kamalhasan14 1 · 0⤊ 0⤋
You cannot solve this using the set or Real numbers.
The answer using the set of complex numbers is 2i (or 2j)
2006-12-20 10:20:56 · answer #10 · answered by Robin the Electrocuted 5 · 1⤊ 0⤋
You mean sqrt(-4)? This equals 2sqrt(-1) = ±2i.
2006-12-20 10:21:14 · answer #11 · answered by Anonymous · 1⤊ 1⤋