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I need to reverse-calculate a %15 discount.
So for example, $10,000 is 85% of x?
How do I solve x?

2006-12-20 02:02:25 · 8 answers · asked by Jay P 1 in Science & Mathematics Mathematics

8 answers

Instead of multiplying the original by the percentage to obtain the new number, you divide the original.

For example, 10000/0.85 = x, where x is the original price before the 85% sale that reduced the price to 10000.

2006-12-20 02:05:08 · answer #1 · answered by thejackallhaslanded 2 · 0 1

Think of this like you would an algebra equation:

10000 = .85x.

Then simply manipulate it as you would any other equation:

10000/.85 = x
11764.71 = x

There is also another way of doing this. If you know the amount deducted from the price which was the 15% discount, then you can set up a similar equation to the one above. But this time you would divide by .15.

1764.71 = .15x

1764.71/.15 = x

11764.73 = x.

Which is very close to our original answer.

2006-12-20 10:34:07 · answer #2 · answered by MathBioMajor 7 · 0 0

You said "$10,000 is 85% of x". In other words,
100 = 85/100 * x. Solve for x.

2006-12-20 10:32:24 · answer #3 · answered by Anonymous · 0 0

divide 10000 by 85 and then multiply by 100

2006-12-20 10:05:13 · answer #4 · answered by heidavey 5 · 1 0

set up a proportion 10000:85::x:100
85x=1000000
x=1000000/85
=11765

2006-12-20 10:28:00 · answer #5 · answered by raj 7 · 0 0

t=n/(100-k*100)/100)

2014-05-07 06:01:51 · answer #6 · answered by Shnurui 2 · 0 0

percent = amount / total * 100%
=> total = amount * 100% / percent
=> x = 10,000 * 100 / 85 = $11,764.7

2006-12-20 10:17:30 · answer #7 · answered by James Chan 4 · 0 0

x= 100000/.85

other examples

60 % of no is 600
then
no is 600/.6

x= selling price / (100-discount)%

2006-12-20 12:45:05 · answer #8 · answered by george t 2 · 0 0

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