Again she turned right and walked 8 km. How far is she from the starting point?
2006-12-20 01:07:27 · 15 answers · asked by raj_paragon 1 in Science & Mathematics ➔ Mathematics
4 km, because the first and last 8 km cancel out since they were in opposite direction.
2006-12-20 03:20:54 · answer #1 · answered by Renaud 3 · 0⤊ 0⤋
This makes a perfect attitude triangle with the factors being x and x+7 with the hypotenuse being 17. So making use of pythagoras theorem we get 17^2 = (x^2) + ((x+7)^2) 289 = 2(x^2) + 14x + forty 9 240 = 2(x^2) + 14x one hundred twenty = x^2 + 7x x^2 + 7x - one hundred twenty = 0 x^2 + 15x - 8x - one hundred twenty = 0 x ( x + 15 ) - 8 ( x + 15 ) =0 (x - 8 ) ( x + 15 ) = 0 x = 8 ( in view that distance won't be able to be destructive for this reason we do away with -15) for this reason entire distance is x + x +7 = 8 + 8 + 7 = 23 km
2016-12-30 16:44:59 · answer #2 · answered by ? 3 · 0⤊ 0⤋
So, draw out how Sudha walked:
+----+
|.....|
|.....|
|.....|
S
Starting at S, she walks 8 km North. Turning right, she walks 4 km East. Turning right again, she walks 8 km South.
The 8 km North, and the 8 km South, basically cancel each other out. The net she traveled is 4 km East. So she is 4 km East of S.
2006-12-20 01:21:05 · answer #3 · answered by Ronald B 2 · 0⤊ 0⤋
4 km
2006-12-20 01:24:34 · answer #4 · answered by Twarita 2 · 0⤊ 0⤋
Walking from S toward N, you have to consider this as walking 8 units along the y-axis. Then turn right and walk 4 more units which is along x-axis 4 units. Use the formula:
x^2 + y^2 = c^2
c is the distant away from the origin or starting point. So, the distant away from starting point is:
c=Squareroot of (x^2 + y^2) = square root of (8^2 + 4^2)
=square root of (64 + 16)
2006-12-20 01:15:49 · answer #5 · answered by Cu Den 2 · 0⤊ 1⤋
Assuming earth flat, I get 4 km east of starting point.
2006-12-20 01:27:08 · answer #6 · answered by Anonymous · 0⤊ 0⤋
Think that the starting point is (0,0) in a coordinate system. Then she walsk 8km directly up the y-axis getting to the point (0,8). Next Sudha walked 4km to the point (4,8) and then down to the point (4,4). So the distance from (4,4) to (0,0) is:
d = sqrt((4-0)^2 + (4-0)^2) = sqrt(16+16) = sqrt(32) = 4sqrt(2)
2006-12-20 01:16:44 · answer #7 · answered by ironduke8159 7 · 0⤊ 1⤋
4 km ,assuming all turns were 90 degree turns
2006-12-20 01:10:50 · answer #8 · answered by jay b 3 · 0⤊ 0⤋
Ronald B is correct.
4 km is the answer.
2006-12-20 01:27:08 · answer #9 · answered by Jerry P 6 · 0⤊ 0⤋
On a flat surface you can use addition of co-ordinates.
Starting co-ordinates (0,0)
Walk 8km North + (8,0) = (8,0)
Turn right and walk 4km East +(0,4)=(8,4)
Turn right and walk 8km South +(-8,0)=(0,4)
Therefore 4km East from where she started
If she is walking on a sphere it all depends on where she started, for example if the journey started at the South Pole she would end up back where she started.
2006-12-20 01:15:48 · answer #10 · answered by DazerUK 2 · 0⤊ 0⤋