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I am not looking for a definitive answer but at least a starting point.

If you want, you can state many parameters:
* Type of shovel (capacity in liter or gallon)
* Density of snow
* Height of snow
* Strengh of shoveler (strong, ordinary, weak for example)
* Actual speed (slow, medium, fast for example)

2006-12-19 02:56:53 · 1 answers · asked by G 1 in Science & Mathematics Engineering

1 answers

2 sq. ft. shovel
medium dense snow (density ~0.35 --> ~20 lb/ft^3)
Pick up a 6-inch layer on the shovel = 1 ft^3 = 20 lb.
Throw it to the side (not carrying it a distance).
Ordinary strength working at medium speed = 5 sec/shovelful
This yields 12 ft^3/minute = 0.34 m^3/minute, or with 0.15 m (6 inch) snow depth, 2.25 m^2/minute.
Hope this helps.

2006-12-20 07:20:01 · answer #1 · answered by kirchwey 7 · 0 0

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