2006-12-18 07:15:52 · 4 answers · asked by slowbowls 2 in Consumer Electronics ➔ Other - Electronics
In series, 1.5v 700mAh + 1.5v 700mAh = 3v 700mAh
In parallel, 1.5v 700mAh + 1.5v 700mAh = 1.5v 1400mAh
You'd need four 1.5v 700mAh batteries to come up with 3v 1400mAh. 2 sets of 2 in series, and then those 2 sets in parallel with each other.
2006-12-18 07:17:44 · answer #1 · answered by Geoff S 6 · 0⤊ 0⤋
Your equation is obviously just put there as a guide to what you wish to know because it is not mathematically or electrically correct
Parallel- each battery is doing half the work of only one battery, hence the mah will double
Series - You are now supplying double the voltage so the 1.5v light bulb would burn out straight away anyway. If the cicuit could handle the doubled voltage it would still only last for however long it took to total 700mah
So the answer is parallel
2006-12-18 15:24:51 · answer #2 · answered by Mad Eng 2 · 0⤊ 0⤋
The capacity adds when connected in parallel.
When connected in series, the cell with the smallest capacity is the overall capacity of the combination.
eg: 2x 1.5v 700mAh cells in parallel = 1.5v 1400mAh battery.
or: 2x 1.5v 700mAh cells in series = 3.0v 700mAh battery.
Cheers.
2006-12-18 15:29:05 · answer #3 · answered by chopchubes 4 · 0⤊ 0⤋
WHAT???
g
2006-12-18 15:18:39 · answer #4 · answered by joeydelponte 2 · 0⤊ 2⤋