http://i143.photobucket.com/albums/r147/rAOL87/circuit1.jpg
Above is a given circuit in which I need to solve for Vb, I1 and I2. I am given Vcc, R6, R7, and Beta. If anyone knows the steps to solving this problem, could you please post them?
thanks in advance!
2006-12-17 09:03:46 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
You need to number your transistors also. Lets number them Q1 starting at the highest, Q2 the one below that and Q3 the one to the right. Then the base current for Q2 is (VCC - VBE) / R7 Then there are two cases where Q2 is fully on and therefore has a voltage drop of about 0.2 Volts. The other case is where Q2 is the current limiting transistor then I1 = Beta * (Base Current Q2). Then you need to solve for the base current of Q1 based on the current and then figure out if Q1 is limiting the current or not. And so on.
Good Luck.
2006-12-17 09:43:37 · answer #1 · answered by rscanner 6 · 0⤊ 0⤋
Assuming that's a elementary emitter circuit, it possibly the capacitor limits amplification of better frequencies because of the fact the reactance of the cap decreases and supplies a right away direction for the sign from base to collector rather of by the junction. The section shift could additionally parent into it.
2016-12-18 15:03:59 · answer #2 · answered by younker 3 · 0⤊ 0⤋
**Ib1=Vcc/R6
**IR5=B1*Ib1
**I1=(Vcc-0.2-0.2)*(R1/(R1+R5))
**I2=(Vcc-0.2)*(R3/(R3+R4))
2006-12-17 11:50:14 · answer #3 · answered by Emad S 1 · 0⤊ 0⤋