Define "standard"...
The formula is "P = V * I". You are asking "I", so give me "P" and "V".
"P" is the amount of Watts, e.g. 100
"V" is the voltage. Usually 240, but 120 is also seen often.
At 240 Volts, a 100 Watt lightbulb uses 0.42 Amps (rounded)
2006-12-17 03:10:37
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answer #1
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answered by Anonymous
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Not stupid. The formula is P=EI where P is the power in watts, E is the voltage and I the current in amps. A 60 watt bulb draws 120 volts times the amps or 60/120 is the amps.
If you don't have power or current then Ohm's law is E=IR where R is the resistance of the circuit in Ohms which now allows substitution into the power formula.
2006-12-17 11:11:53
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answer #2
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answered by St N 7
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Amps = Power / Volts
at 120 volts, a 100 watt bulb draw a little less than an amp. You can scale from there.
2006-12-17 11:21:31
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answer #3
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answered by Gene 7
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Divide watts by volts (120 for US, 240 for most other countries). A 60 watt buld (in US) draws 1/2 amp.
2006-12-17 11:46:21
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answer #4
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answered by Anonymous
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It depends on your utility provider. Say you have 110v line and you have a 50-watt bulb. That translates to 50/110 = 0.45 ampere. On the other hand, if you have a 220v line, then the consumption would be 50/220 = 0.23 ampere
2006-12-17 11:14:05
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answer #5
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answered by Del S 2
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It's depend on the wattage of the bulb. As you know, using W=VI equation you can calculate the current flow through the bulb.For a example if W=100w and V=230v then I=W/V=0.43A
2006-12-17 11:18:03
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answer #6
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answered by mangala a 1
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P=V*I
I=P/V
standard light bulbs are (60,75,100) Watts
Voltages depend on the country you are in, USA is 110-120V, other countries might be 220-240V
YOU DO THE MATH !!!!!
2006-12-17 13:42:44
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answer #7
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answered by T.M.M. 4
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0.2 to 0.8 amps
2006-12-17 11:28:40
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answer #8
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answered by Anonymous
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