The three dimensions of a rectangular solid have lengths of 32, 36 and 48. find the length of a main diagonal of the rectangular solid.
2006-12-16 11:19:25 · 5 answers · asked by Quagmire77 1 in Science & Mathematics ➔ Engineering
Find the diagonal of any side, using two of the three dimensions to calculate the hypotenuse. Then, use that diagonal with the unused dimension to find the hypotenuse, which is the "main" diagonal. Note that all 4 diagonals of the solid are the same length.
2006-12-16 11:25:05 · answer #1 · answered by arbiter007 6 · 0⤊ 0⤋
In a dice of part length s the face diagonal, d, say, is srt2 and d^2 = 2s^2. Now, if we label the significant diagonal (nook to nook) of the dice D,say, then D^2 = s^2 + d^2 = 3s^2 and D = srt3. So a one meter dice has a significant diagonal of (rt3) m., approx = a million.73205 m.
2016-11-26 23:12:01 · answer #2 · answered by Anonymous · 0⤊ 0⤋
square root of (32^2+36^2+48^2)
^2 means squared
2006-12-16 11:23:09 · answer #3 · answered by Anonymous · 0⤊ 0⤋
68 (sqrt(32^2+36^2+48^2))
2006-12-16 11:23:58 · answer #4 · answered by Anonymous · 0⤊ 0⤋
that would be 48 wouldnt it?
2006-12-16 11:21:09 · answer #5 · answered by david 2 · 0⤊ 0⤋